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3 years ago

Find all numbers whose absolute value is – 3.

Mathematics

1 answer:

Gwar [14]3 years ago

7 0

Answer:

remember that $|x|=x$ if $x\geq0$ and $|x|=-x \; \text{ if } x\leq 0$ . This means that $|x|$ always is a positive number.

Then, there are no numbers such that $|x|=-3$ because -3 is a negative number.

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The inventory of a store 2 years ago was worth $45,000. This year it is worth $49,500. What is the percent increase?

UkoKoshka [18]

It is 0.4500% hope this helps

7 0

3 years ago

A tangerine juice container is in the shape of a rectangular prism. The width is 26

geniusboy [140]

Answer:

V = 26d^2 + 624d

Step-by-step explanation:

Volume = Width x Depth x Height

V = 26 (d) (d+24)

Now distribute 26

V = 26d(d+24)

Then distribute 26d

V = 26d^2 + 624d

6 0

3 years ago

23 and 24 I need help please

Gnoma [55]

Answer:

They should purchase the snack with the purple box. This is the answer for 23, i don't know what 24 is sorry.

Step-by-step explanation:

24÷3=8

8×5=40

so the first snacks would cost them $40.

then:

24÷4=6

6×6=36

so the second snacks would cost them $36

5 0

3 years ago

Which is equivalent to 4x/x-7 - x+7/x

spin [16.1K]

Answer:

The answer to your question is the second choice

Step-by-step explanation:

4x/ (x - 7) - (x +7) / x

- Find the greatest common factor from x and (x - 7)

GCF = x(x - 7)

- Substract the terms

[4x(x) - (x + 7)(x - 7)] / x(x - 7)

- Simplify

[ 4x² - x² + 49] / x(x - 7)

[ 3x² + 49] / x(x - 7)

- Result

3x² + 49 / x(x - 7)

6 0

3 years ago

50 PTS ANSWER ALL <3333333

11Alexandr11 [23.1K]

QUESTION 33

The length of the legs of the right triangle are given as,

6 centimeters and 8 centimeters.

The length of the hypotenuse can be found using the Pythagoras Theorem.

${h}^{2} = {6}^{2} + {8}^{2}$

${h}^{2} = 36+ 64$

${h}^{2} = 100$

$h = \sqrt{100}$

$h = 10cm$

Answer: C

QUESTION 34

The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.

The length of the other leg can be found using the Pythagoras Theorem,

${l}^{2} + {33}^{2} = {55}^{2}$

${l}^{2} = {55}^{2} - {33}^{2}$

${l}^{2} = 1936$

$l = \sqrt{1936}$

$l = 44cm$

Answer:B

QUESTION 35.

We want to find the distance between,

(2,-1) and (-1,3).

Recall the distance formula,

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the values to get,

$d=\sqrt{( - 1-2)^2+(3- - 1)^2}$

$d=\sqrt{( - 3)^2+(4)^2}$

$d=\sqrt{9+16}$

$d=\sqrt{25}$

$d = 5$

Answer: 5 units.

QUESTION 36

We want to find the distance between,

(2,2) and (-3,-3).

We use the distance formula again,

$d=\sqrt{( - 3-2)^2+( - 3- 2)^2}$

$d=\sqrt{( - 5)^2+( - 5)^2}$

$d=\sqrt{25+25}$

$d=\sqrt{50}$

$d=5\sqrt{2}$

Answer: D

8 0

3 years ago

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