Answer:
The time interval when is at
The distance is 106.109 m
Step-by-step explanation:
The velocity of the second particle Q moving along the x-axis is :
So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.
We are also to that :
between
The schematic free body graphical representation of the above illustration was attached in the file below and the point when is at 4 is obtained in the parabolic curve.
So, is at
Taking the integral of the time interval in order to determine the distance; we have:
distance =
=
= By using the Scientific calculator notation;
distance = 106.109 m
Answer:
16
Step-by-step explanation:
The way it's written it's
Simplify the following:
7 X^3 + 4 X^2 + 2 X^2 + 3 X + X + 2 + 5
Grouping like terms, 7 X^3 + 4 X^2 + 2 X^2 + 3 X + X + 2 + 5 = 7 X^3 + (4 X^2 + 2 X^2) + (3 X + X) + (2 + 5):7 X^3 + (4 X^2 + 2 X^2) + (3 X + X) + (2 + 5)
4 X^2 + 2 X^2 = 6 X^2:
7 X^3 + 6 X^2 + (3 X + X) + (2 + 5)
3 X + X = 4 X:
7 X^3 + 6 X^2 + 4 X + (2 + 5)
2 + 5 = 7:Answer: 7 X^3 + 6 X^2 + 4 X + 7