Question

A passenger walks from one side of a ferry to the other as it approaches a dock.Passenger's velocity is 1.55 m/s due north relative to the ferry, and 4.50 m/s at an angle of 30.0° west of north relative to the water. (A)What is the magnitude of the ferry's velocity relative to the water? (B) What is the direction of the ferry's velocity relative to the water?

Answer 1

Answer:$\theta =33.22^{\circ}$

Explanation:

Given

Velocity of Passenger w.r.t to Ferry

$v_{pf}=v_p-v_f=1.55\hat{j}$-------1

Velocity of Passenger w.r.t to water

$v_{pw}=v_p-v_w=4.5\left ( -\hat{i}+\hat{j}\right )$--------2

Subtract 2 from 1

$v_f-v_w=-4.5\hat{i}+2.95\hat{j}$

(b)direction

$tan\theta =\frac{2.95}{4.5}=0.655$

$\theta =33.22^{\circ}$ North of west