(B)
Explanation:
Centripetal means "towards the center" so the acceleration vector of an object undergoing UCM is always pointed towards the center.
Complete Question
The complete question is shown on the first uploaded image
Answer:
The temperature change is 
Explanation:
From the question we are told that
The velocity field with which the bird is flying is 
The temperature of the room is 
The time considered is t = 10 \ seconds
The distance that the bird flew is x = 1 m
Given that the bird is inside the room then the temperature of the room is equal to the temperature of the bird
Generally the change in the bird temperature with time is mathematically represented as
![\frac{dT}{dt} = -0.4 \frac{dy}{dt} -0.6\frac{dz}{dt} -0.2[2 * (5-x)] [-\frac{dx}{dt} ]](https://tex.z-dn.net/?f=%5Cfrac%7BdT%7D%7Bdt%7D%20%3D%20-0.4%20%5Cfrac%7Bdy%7D%7Bdt%7D%20-0.6%5Cfrac%7Bdz%7D%7Bdt%7D%20-0.2%5B2%20%2A%20%20%285-x%29%5D%20%5B-%5Cfrac%7Bdx%7D%7Bdt%7D%20%5D)
Here the negative sign in
is because of the negative sign that is attached to x in the equation
So
![\frac{dT}{dt} = -0.4v_y -0.6v_z -0.2[2 * (5-x)][ -v_x]](https://tex.z-dn.net/?f=%5Cfrac%7BdT%7D%7Bdt%7D%20%3D%20-0.4v_y%20%20-0.6v_z%20-0.2%5B2%20%2A%20%20%285-x%29%5D%5B%20-v_x%5D)
From the given equation of velocity field



So
substituting the given values of x and t
Answer:
HP = 27.08 hp
Explanation:
The complete question has a theoretical flow rate of 18.2 GPM. So, to find the input horsepower, we will use the following formula:
HP = QP/1714(E)
where,
HP = Input Horse Power = ?
Q = Volume Flow Rate in Gallons Per Minute (GPM) = 18.2 GPM
P = Outlet Pressure in psi = 2372 psi
E = Mechanical Efficiency = 0.93
Therefore,
HP = (18.2 GPM)(2372 psi)/(1714)(0.93)
<u>HP = 27.08 hp</u>
Answer:
162.8 K
Explanation:
initial current = io
final current, i = io/8
Let the potential difference is V.
coefficient of resistivity, α = 43 x 10^-3 /K
Let the resistance is R and the final resistance is Ro.
The resistance varies with temperature
R = Ro ( 1 + α ΔT)
V/i = V/io (1 + α ΔT )
8 = 1 + 43 x 10^-3 x ΔT
7 = 43 x 10^-3 x ΔT
ΔT = 162.8 K
Thus, the rise in temperature is 162.8 K.