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dexar [7]
3 years ago
15

Where is the Long Head located? Outside of the Arm Inside of the Arm On the Shoulder

Physics
2 answers:
rjkz [21]3 years ago
4 0

Answer:

On the shoulder

Explanation:

Basile [38]3 years ago
3 0

Answer:

The biceps muscle is located at the front of your upper arm. The muscle has two tendons that attach it to the bones of the scapula bone of the shoulder and one tendon that attaches to the radius bone at the elbow. The tendons are tough strips of tissue that connect muscles to bones and allow us to move our limbs.

Explanation:

Glad i could help pls give brainliest and or thanks

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A car travels 35 km west and 90 km north in two hours what is its average velocity?
blagie [28]
Average velocity =  Total Displacement / Total time taken

Total displacement is the distance from starting to end point.

35km west then 90km north. When you will draw this and connect starting to end point. You will get a right angled triangle. 

So displacement = \sqrt{35^2+90^2}

= 96.56 km

So, Total displacement = 96.56 km

So, Average Velocity = 96.56 / 2  = 48.28 km/hr
8 0
4 years ago
¿Qué cantidad de calor se desprende cuando 125 g de vapor de agua a 140 ºC se enfrían y congelan produciendo 125 g de hielo a -1
tensa zangetsu [6.8K]

Answer:

i dont know

Explanation:

7 0
3 years ago
A truck starts from rest with an acceleration of 0.3 m/ S^2 find its speed in km/h when it has moves through 150 m​
Nadya [2.5K]

Answer:

9.5 m/s

Explanation:

Distance, S = 150m

Acceleration, a = 0.3 m/s^2

Initial velocity, u = 0 m/s

Final velocity, v

Use kinematics equation

v^2 - u^2 = 2aS

v^2 - 0 = 2*0.3*150 = 90

v = sqrt(90) = 9.49 m/s

3 0
3 years ago
Read 2 more answers
Calculate the mass of air of density 1.2kgm-3 in a room of dimensions 8m by 6m by 4m.
77julia77 [94]

Answer:

230.4kg

Explanation:

volume of the room = l× b×h

volume= 8×6×4

volume=192m3

density= mass/volume

hence mass= density × volume

mass= 1.2kgm-3 × 192m3

mass= 230.4kg

5 0
2 years ago
A conducting coil of 1470 turns is connected to a galvanometer, and the total resistance of the circuit is 56.0 . The area of ea
Damm [24]

Answer:

 B = - 1.51 10⁻⁷ T

Explanation:

For this exercise we can use Faraday's law of induction

          E = - - \frac{d \phi _B}{dt} = - \frac{d (B A cos \theta )}{dt}

           

In this case, they indicate that the normal and the magnetite field are in the same direction, so the angle is zero (cos 0 = 1), they give the area of ​​the loop A = 4.32 10⁻⁴ m² and since we have N = 1470 turns in each one a voltage is induced

          E = - N B A

          B = -E A / N               (1)

we find the induced voltage with ohm's law

         V = i R

where the current is defined by

         i = Q / t

we substitute

          V = Q R / t

 

let's calculate

         V = 9.18 10-3 56.0 / t

We must assume a time normally is t = 1 s

         V = 0.514 V

this is the voltage in the circuit which must be the induced voltage V = E

we substitute in 1

         B = - 0.514 4.32 10⁻⁴ / 1470

         B = - 1.51 10⁻⁷ T

3 0
3 years ago
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