Explanation:
Sorry but the question is incomplete
Answer:
r₂/r₁ = 1.82
Explanation:
The electric field due to a point charge, has the following expression:
For a distance r₁, the magnitude of the electric field is 395 N/C, so we can solve for r₁², as follows:
r₁² = (1)
For a distance r2, the magnitude of the electric field is 119 N/C, so we can solve for r₂², as follows:
r₂² =
We can find the quotient r₂/r₁, from (1) and (2):
r₂/r₁ = = 1.82
Answer:
E=147898.01J
Explanation:
A 5.0-kg cannonball is fired over level ground with a velocity of 2.00 ⨯ 102 m/s at an angle of 25° above the horizontal. Just before it hits the ground its speed is 150 m/s. Over the entire trip, find the change in the thermal energy of the cannonball and air
firstly , we look for the time of flight it takes to make the projectile path
T=2Usin∅/g
take g= 9.81m/s
T=2*200sin25/(9.81)
T=17.23Secs
energy is force *distance
E=f*d
f=m*g
f=5*9.81
f=49.05N
s=distance
s=(v+u)T/2
s=(150+200)17.23/2
s=3015.25m
49.05N*3015.25m
E=147898.01J
Answer and Explanation:
The collision of particles (or moleclues) would need to be required. Say there are two gasses, one with a higher temperature and one with a lower one. The kenetic energy in the moleclues can move in random directions, and start to bump into each other. If the warmer particle collides with the cooler one then the warmer particle would be transferring <em>heat </em>which is thermal energy.<em> T</em>he particles colliding would be called <em>thermal conduction</em>.