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Maru [420]
4 years ago
6

A roller coaster speeds up with constant acceleration for 2.3 s until it reaches a velocity of 35 m/s. During this time, the rol

ler coaster travels 41m. What is the initial velocity of the roller coaster before it begins to accelerate?
Physics
1 answer:
Arada [10]4 years ago
5 0

The initial velocity is 0.65 m/s

Explanation:

The motion of the roller coaster is a uniformly accelerated motion, so we can solve the problem by using the following suvat equation:

s=(\frac{u+v}{2})t

where

s is the displacement

u is the initial velocity

v is the final velocity

t is the time

For the roller coaster in this problem:

v = 35 m/s

t = 2.3 s

s = 41 m

Solving the equation for u, we find the initial velocity:

u=\frac{2s}{t}-v=\frac{2(41)}{2.3}-35=0.65 m/s

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

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2. El sonido de una ballena es en especial de frecuencia baja, pero existe una especie de ballena la Whalien cuya frecuencia es
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Answer:

The sound of a whale is especially low frequency, but there is a species of whale the Whalien whose frequency is 52 Hz, if the propagation speed of the wave is 1400m / s What will be its period in the water and the air? And what will be the wavelength in each medium? Remember that the propagation speed in air is 340m / s

Explanation:

From wave equation, the speed, wavelength and frequency is related using

V = fλ

Where

V is the speed

f is the frequency

And λ is the wavelength

So,

The frequency of the whale is

f = 52Hz

The speed in water is V_w = 1400m/s

The speed in air is V_a = 340m/s

We want to find the period in each medium, the period is related to the frequency and since the frequency is constant.

Then, period in equal in both medium

T = 1 / f

T_w = T_a = 1 / f

T = 1 / 52

T = 0.0192 seconds

We want to find the wavelength in each medium

For water,

V = fλ

V_w = f × λ_w

Then,

λ_w = V_w / f.

λ_w = 1400 / 52 = 26.92 m

The wavelength in water is 26.92m

Now, in air

V = fλ

V_a = f × λ_a

Then,

λ_a = V_a / f.

λ_a = 340 / 52 = 6.54 m

The wavelength in air is 6.54 m

In Spanish

De la ecuación de onda, la velocidad, la longitud de onda y la frecuencia se relacionan usando

V = fλ

Dónde

V es la velocidad

f es la frecuencia

Y λ es la longitud de onda

Entonces,

La frecuencia de la ballena es

f = 52Hz

La velocidad en el agua es V_w = 1400m / s

La velocidad en el aire es V_a = 340m / s

Queremos encontrar el período en cada medio, el período está relacionado con la frecuencia y dado que la frecuencia es constante.

Luego, período igual en ambos medios

T = 1 / f

T_w = T_a = 1 / f

T = 1/52

T = 0.0192 segundos

Queremos encontrar la longitud de onda en cada medio

Para agua,

V = fλ

V_w = f × λ_w

Entonces,

λ_w = V_w / f.

λ_w = 1400/52 = 26,92 m

La longitud de onda en el agua es de 26,92 m.

Ahora en el aire

V = fλ

V_a = f × λ_a

Entonces,

λ_a = V_a / f.

λ_a = 340/52 = 6,54 m

La longitud de onda en el aire es de 6.54 m.

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