The acceleration is 2 mph/min
Explanation:
The acceleration of an object is the rate of change of velocity. It is defined as follows:
where
v is the final velocity
u is the initial velocity
t is the time taken for the velocity to change from u to v
For the car in this problem, we have (taking North as positive direction):
u = 25 mph
v = 35 mph
t = 5 min
Substituting into the equation, we find the acceleration:
Learn more about acceleration:
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We have no way to say what the illustration represents, mainly because
you haven't given us a way to see the illustration.
<span>However, the process that all stars, including our sun, use to continuously
produce energy is nuclear fusion.</span>
Answer:
Equilibrium
Explanation:
An object is in equilibrium when the vector sum of the force acting on the object is equal to zero.
A body in equilibrium is at state of rest of rest or in motion with no external force acting on it.
- The resultant of all forces acting on the body is zero.
- In this case there is no net force and the body will be at rest.
Answer:
Check explanation
Explanation:
In the formation of calcium fluoride we take calcium and fluorine.
in elemental form calcium exist in solid form and fluorine in gaseous form.
formation of compound takes place to complete their octet, in case of calcium need to remove two electron and need to add one elecron in fluorine to complete their octet so two electron will ransferred from calcium to two fluorine atom.
Answer:
a) ω = 9.86 rad/s
b) ac = 194. 4 m/s²
c) minimum coefficient of static friction, µs = 19.8
Explanation:
a) angular speed, ω = 2πf, where f is frequency of revolution
1 rps = 6.283 rad/s, π = 3.142
ω = 2 * 3.14 * 0.25 * 6.28
ω = 9.86 rad/s
b) centripetal acceleration, a = rω²
where r is radius in meters; r = 200 cm or 2 m
a = 2 * 9.86²
a = 194. 4 m/s²
c) µs = frictional force/ normal force
frictional force = centripetal force = ma; where a is centripetal acceleration
normal force = mg; where g = 9.8 m/s²
µs = ma/mg = a/g
µs = 194.4 ms⁻²/9.8 ms⁻²
c) minimum coefficient of static friction, µs = 19.8
