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Artist 52 [7]
4 years ago
8

At a distance r1 from a point charge, the magnitude of the electric field created by the charge is 395 N/C. At a distance r2 fro

m the charge, the field has a magnitude of 119 N/C. Find the ratio r2/r1.
Physics
1 answer:
Ksenya-84 [330]4 years ago
7 0

Answer:

r₂/r₁ = 1.82

Explanation:

The electric field due to a point charge, has the following expression:

E =\frac{k*q}{r^{2}}

For a distance r₁, the magnitude of the electric field is 395 N/C, so we can solve for r₁², as follows:

r₁² = \frac{k*q}{395 N/C} } (1)

For a distance r2, the magnitude of the electric field is 119 N/C, so we can solve for r₂², as follows:

r₂² = \frac{k*q}{119 N/C} }

We can find the quotient r₂/r₁, from (1) and (2):

r₂/r₁ =\sqrt{395/119} = 1.82

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