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lions [1.4K]
4 years ago
5

The value of a car bought new for $28900 decreases 15% each year. Identify the function for the value of the car. Does the funct

ion represent growth or decay?
Mathematics
1 answer:
Eva8 [605]4 years ago
8 0

Answer:

<u>V (t) = 28,900 - 4,335t</u>

<u>The function clearly represent a decay</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Value of the car = $ 28,900

Annual depreciation = 15% = 0.15

2. Identify the function for the value of the car. Does the function represent growth or decay?

Let y represent the value of the car after t years of utilization, let p the price of the car and d, the annual depreciation, therefore:

V (t) = p - (d * t * p)

Replacing with the values we know:

V (t) = 28,900 - (0.15 * t * 28.900)

V (t) = 28,900 - (0.15 * t * 28.900)

<u>V (t) = 28,900 - 4,335t</u>

<u>The function clearly represent a decay.</u>

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likoan [24]
I think it’s an regular because it looks like an rectangle
8 0
3 years ago
Help me pls this is very hard for me and plus i gotta turn this in tomorrow
faltersainse [42]

Answer: \Large\boxed{x=40^\circ}

Step-by-step explanation:

<u>Given information</u>

∡ 1 = 90°

∡ 2 = 50°

∡ 3 = x°

Total Angle = 180° <em>(Triangle angle sum theorem)</em>

<u>Given formula</u>

∡ 1 + ∡ 2 + ∡ 3 = Total Angle

<u>Substitute values into the formula</u>

(90) + (50) + (x) = (180)

<u>Combine like terms</u>

140 + x = 180

<u>Subtract 140 on both sides</u>

140 + x - 140 = 180 - 140

\Large\boxed{x=40^\circ}

Hope this helps!! :)

Please let me know if you have any questions

6 0
2 years ago
Plzz I asked this three times! The Functions r and s are defined as follows.
Lana71 [14]

Answer:

s(r(2)) = 6

Step-by-step explanation:

You would first solve for r(2). You then input r(2) which equals -2 into s(r(2)).

r(x)= -2x + 2

r(2)= -2(2) + 2

r(2)= -4 +2

r(2)= -2

s(x)=x² + 2

s(r(2)) = (-2)² +2

s(r(2)) = 6

6 0
3 years ago
If (he)={(0,1),(2,3),(-4,1)}, find h^-1(x)
ololo11 [35]

The given function is

h(x) = \{ (0,1), (2,3), (-4, 1) \}

The inverse function is

h^{-1}(x) = \{ (1,0), (3,2), (1,-4)\}

To get the inverse, we swap each x and y coordinate.

The rule is (x,y) \to (y,x)

So that's why the point (0,1) becomes (1,0) for instance.

3 0
3 years ago
F(x+1)+f(x+2)=2x+3; f(x)=?
Rama09 [41]

Answer:

F=\frac{-xf+f+2x}{x+1};\quad \:x\ne \:-1

Step-by-step explanation:

1. \mathrm{Subtract\:}f\left(x+2\right)\mathrm{\:from\:both\:sides}\\&#10;F\left(x+1\right)+f\left(x+2\right)-f\left(x+2\right)=2x+3f-f\left(x+2\right)&#10;&#10;

2. \mathrm{Simplify}\\&#10;F\left(x+1\right)=-xf+f+2x\\&#10;

3. \mathrm{Divide\:both\:sides\:by\:}x+1;\quad \:x\ne \:-1\\&#10;\frac{F\left(x+1\right)}{x+1}=-\frac{xf}{x+1}+\frac{f}{x+1}+\frac{2x}{x+1};\quad \:x\ne \:-1

4. \mathrm{Simplify}\\&#10;F=\frac{-xf+f+2x}{x+1};\quad \:x\ne \:-1

Final Answer: F=\frac{-xf+f+2x}{x+1};\quad \:x\ne \:-1

4 0
3 years ago
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