Can somebody plz help me with surveys in math?

What is the solution to the system of equations?<br> 2x+3y=-11<br> y=x-2

zmey [24]

Answer:4

Step-by-step explanation: this but u can use.kkk p h o t o m a t h

5 0

2 years ago

A small bar of gold measures 40 mm by 25 mm by 2 mm. One cubic millimeter of gold weighs about 0.0005 ounce. Find the volume in

slamgirl [31]

I'm believing that you have the measurements in the right order, lwh, the Volume would be 5,000. You'd take 40 x 25 x 2= 5,000.

The weight is 2.5 oz. You get this answer by taking the Volume, 5,000, and multiply it by 0.0005 and you get 2.5 ounces.

I hope this helps!

8 0

2 years ago

A number is written with the following factorization:2² x 3 x 5⁴ x 8 x 11².Is this factorization a prime factorization? Explain

BigorU [14]

Answer:

NO, this is not prime factorization.

The correct prime factorization is = $2^{5} X 3 X 5^{4} X 11^{2}$

Step-by-step explanation:

Prime factorization means, writing the given number as product of prime numbers.

In the above case, in the prime factorization,<em> the number 8 is present which is not a prime number.</em>

8 can be further represented as product of prime numbers as,

$8 = 2^{3}$

Now the prime factorization reduces to,

= $2^{2} X 3 X 5^{4} X 2^{3} X 11^{2}$

= $2^{5} X 3 X 5^{4} X 11^{2}$

7 0

2 years ago

$800 principal earning 7%, compounded annually, after 4 years

Jlenok [28]

Answer:

$1050

Step-by-step explanation:

<h2><u>formula for compound interest method:</u></h2>

A = P ( 1 + r/100)^n

A is actual amount

r is the rate of interest

P is the principle

n is the number of years

A = 800 (1 * 7/100)^4

= 1048.637

to 3sf = <u>$1050</u>

6 0

3 years ago

Solve the given system of equations utilizing either the substitution or addition method.

Nataly [62]

Answer:

Value of x=4 and y=-13/3

Step-by-step explanation:

We need to solve the systems of equations

$5x+3y=7 \ and \ \frac{3}{2}x-\frac{3}{4}y =9\frac{1}{4}$

Solving using substitution method:

Let:

$5x+3y=7---eq(1) \\ \frac{3}{2}x-\frac{3}{4}y =9\frac{1}{4}---eq(2)$

Find value of x from eq(1) and put in eq(2)

$5x+3y=7\\5x=7-3y\\x=\frac{7-3y}{5}$

Put value of x in eq(2)

$\frac{3}{2}(\frac{7-3y}{5}) -\frac{3}{4}y =\frac{37}{4}\\\frac{21-9y}{10} -\frac{3}{4}y =\frac{37}{4}\\Taking \ LCM\\\frac{21*2-9y*2-3y*5}{20} =\frac{37}{4}\\\frac{42-18y-15y}{20} =\frac{37}{4}\\42-33y=\frac{37}{4}*20\\42-33y=185\\-33y=185-42\\-33y=143\\y=\frac{143}{-33}\\y=-\frac{13}{3}$

Now, finding value of x by putting value of y in eq(1)

$x=\frac{7-3y}{5}\\x= \frac{7-3(-\frac{13}{3}) }{5}\\x=\frac{7+13}{5}\\x=\frac{20}{5}\\x=4$

So, Value of x=4 and y=-13/3

4 0

2 years ago