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rjkz [21]
3 years ago
8

Will give max points!!!!!! HELPPPPPP PLEASEEEEEE

Mathematics
2 answers:
Alexandra [31]3 years ago
8 0
Ummmm uh.....fid the perimiter and diamiter and multiply them...
FrozenT [24]3 years ago
7 0
2. SAS
3. Triangle RXQ is congruent to triangle SXT by SAS
4. Angle Z is congruent to Angle C
5.Angle T is congruent to Angle D
6. CE is congruent to LM
 Hope this helps. I answered as many as I could.
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Cuál es la exprecion <br>equibalente a 4x² 20x + 25 es:​
choli [55]

Answer:¿Es 4x² + 20x o 4x-20x?

Step-by-step explanation:

3 0
3 years ago
Gemma had $2,054 in her checking account. She wrote a check for $584 to pay the rent on her apartment. After the landlord cashed
gtnhenbr [62]
This can be solved by subtracting 584 from 2,054.
2,054-584
=1470

Gemma would have $1470 left in her checking account.

Hope this helps!
-Benjamin
8 0
3 years ago
Read 2 more answers
What is the coefficient in the term k?<br> A.0<br> B.1<br> C.2<br> D.k
DaniilM [7]

Answer:

1

Step-by-step explanation:

because the is an invisible 1 in an letter

5 0
3 years ago
The angular velocity of a fan blade is 6.2 radians per second.
MA_775_DIABLO [31]

Answer:

94.7 revolutions

Step-by-step explanation:

In the question above, we are given the following values for the fan

Angular velocity = 6.2 radians per seconds

Time = 1.6 minutes.

Step 1

We would convert the time given to seconds

1 minute = 60 seconds

1.6 minutes = ?

We cross multiply

1.6 minutes × 60 seconds

= 96 seconds

Step 2

Number of revolutions made by the fan is calculated as :

Angular velocity(rad/s)

× time(seconds)

Number of revolutions = 6.2 radians per seconds × 96 seconds

=595.2 radians

Converting from radians to revolution

1 radian = 0.159155 revolutions

595.2 radians =

Cross multiply

= 595.2 radians × 0.159155 revolutions

= 94.729056 revolutions.

Approximately to the nearest tenth = 94.7 revolutions.

Therefore, the number of revolutions the fan blade makes in 1.6 minutes is 94.7 revolutions.

8 0
3 years ago
Write an equation for a circle with a diameter that has endpoints at (–4, –7) and (–2, –5). Round to the nearest tenth if necess
Zinaida [17]

since we know the endpoints of the circle, we know then that distance from one to another is really the diameter, and half of that is its radius.

we can also find the midpoint of those two endpoints and we'll be landing right on the center of the circle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[-2-(-4)]^2+[-5-(-7)]^2}\implies d=\sqrt{(-2+4)^2+(-5+7)^2} \\\\\\ d=\sqrt{2^2+2^2}\implies d=\sqrt{2\cdot 2^2}\implies d=2\sqrt{2}~\hfill \stackrel{~\hfill radius}{\cfrac{2\sqrt{2}}{2}\implies\boxed{ \sqrt{2}}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-2-4}{2}~~,~~\cfrac{-5-7}{2} \right)\implies \left( \cfrac{-6}{2}~,~\cfrac{-12}{2} \right)\implies \stackrel{center}{\boxed{(-3,-6)}} \\\\[-0.35em] ~\dotfill

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3}{ h},\stackrel{-6}{ k})\qquad \qquad radius=\stackrel{\sqrt{2}}{ r} \\[2em] [x-(-3)]^2+[y-(-6)]^2=(\sqrt{2})^2\implies (x+3)^2+(y+6)^2=2

4 0
3 years ago
Read 2 more answers
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