A 12- V battery powers a series circuit that contains two lightbulbs. The voltage across one of the lightbulbs is 8 V. What frac
tional part of the circuits total energy is transformed in the second lightbulb?
1 answer:
Answer:
1/3
Step-by-step explanation:
12-8=4
4/12 = 1/3
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Hope This Helps ^_^
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