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3 years ago

6

A 12- V battery powers a series circuit that contains two lightbulbs. The voltage across one of the lightbulbs is 8 V. What frac

tional part of the circuits total energy is transformed in the second lightbulb?

1 answer:

Alisiya [41]3 years ago

8 0

Answer:

1/3

Step-by-step explanation:

12-8=4

4/12 = 1/3

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Solve the given equation by completing the square.

Dmitriy789 [7]

Answer:

a = -4, b = 3 and c = 6 (OR)

a = -4, b = -3 and c = 6

Step-by-step explanation:

$x^{2} +8x = 38$

Add 16 to both sides.

$x^{2} +8x+16 = 38 + 16$

$(x+4)^{2} =54$

$x + 4 = \sqrt{54}$ or $x + 4 = -\sqrt{54}$

$x+4=3\sqrt{6}$ or $x+4=-3\sqrt{6}$

$x=-4+3\sqrt{6}$ or $x=-4-3\sqrt{6}$

Therefore, a = -4, b = 3 and c = 6 (OR)

a = -4, b = -3 and c = 6

6 0

3 years ago

Read 2 more answers

Find the number of roots for each equation.<br> 5. 5x4 + 12x3 – x2 + 3x + 5 = 0

pav-90 [236]

Answer:

The number of roots for equation $5x^4 + 12x^3 – x^2 + 3x + 5 = 0$ is 4 .

Step-by-step explanation:

Here, the given function polynomial is :

$P(x) : 5x^4 + 12x^3 – x^2 + 3x + 5 = 0$

The Fundamental Theorem of Algebra says that a polynomial of degree n will have exactly n roots (counting multiplicity).

Now here, the degree if the polynomial is 4 (highest power of variable x).

So, according to the Fundamental Theorem, the given polynomial can have AT MOST 4 roots, counting Multiplicity.

Hence, the number of roots for equation $5x^4 + 12x^3 – x^2 + 3x + 5 = 0$ is 4 .

7 0

3 years ago

The curve given by x=sin(t),y=sin(t+sin(t)) has two tangent lines at the point (x,y)=(0,0). List both of them in order of increa

SOVA2 [1]

Answer:

y = 0

y =2x

Step-by-step explanation:

Given parametric equations:

x (t) = sin (t)

y (t) = sin (t + sin (t))

The slope of the curve at any given point is given by dy / dx we will use chain rule to find dy / dx

(dy / dx) * (dx / dt) = (dy / dt)

(dy / dx) = (dy / dt) / (dx / dt)

Evaluate dx / dt and dy / dt

dx / dt = cos (t)

dy / dt = cos (t + sin (t)) * (1+cos (t))

Hence,

dy / dx = (1+cos(t))*cos(t + sin (t))) / cos (t)

@Given point (x,y) = 0 we evaluate t

0 = sin (t)

t = 0 , pi

Input two values of t and compute dy / dx

@ t = 0

dy / dx = (1 + cos (0))*cos (0 + sin (0))) / cos (0)

dy / dx = (1+1)*(1) / (1) = 2 @ t = 0

@t = pi

dy / dx = ( 1 + cos (pi))* cos (pi + sin (pi)) / cos (pi)

dy / dx = (1-1) * (-1) / (-1) = 0 @ t = pi

The corresponding gradients are 0 and 2 in increasing order and their respective equations are:

y = 2x

y = 0

5 0

2 years ago

Examine the system of equations.

MrMuchimi

answer:

$x = - 2 \\ y = 2 \\ \\ ( - 2, \: 2)$

explanation:

$y = - \frac{1}{2} x + 1 \\ y = 2x + 6 \\ first \: equation \: add \: \frac{1}{2} from \: both \\ sides \\ \\ second \: equation \: subtract \: 2x \: from \\ both \: sides \\ \\ y + \frac{1}{2} x = 1 \\ y - 2x = 6 \\ solve \: the \: first \: equation \\ \\ y + \frac{1}{2} x = 1 \\ subtract \: \frac{x}{2} from \: both \: sides \\ \\ y = - \frac{1}{2} x + 1 \\ substitute \: - \frac{x}{2} + 1 \: for \: y \: in \: the \\ other \: equation \\ \\ - \frac{1}{2} x + 1 - 2x = 6 \\ add \: \frac{1}{2} x \: to \: 2x \\ \\ - \frac{5}{2} x + 1 = 6 \\ subtract \: 1 \: from \: both \: sides \\ \\ - \frac{5}{2} x = 5 \\ divide \: both \: sides \: by \: - \frac{5}{2} \\ \\ x = - 2 \\ substitute \: the \: value \: of \: x \: into \\ an \: equation \\ \\ y = - \frac{1}{2} ( - 2) + 1 \\ distribute \\ \\ y = 1 + 1 \\ add \\ \\ y = 2 \\ \\ ( - 2, \: 2)$

7 0

2 years ago

What is 25% less than x

vladimir2022 [97]

Answer:

3/4x

Step-by-step explanation:

5 0

3 years ago