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3 years ago

6

A 12- V battery powers a series circuit that contains two lightbulbs. The voltage across one of the lightbulbs is 8 V. What frac

tional part of the circuits total energy is transformed in the second lightbulb?

1 answer:

Alisiya [41]3 years ago

8 0

Answer:

1/3

Step-by-step explanation:

12-8=4

4/12 = 1/3

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Answer:

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2 years ago

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Dovator [93]

Answer:

$x=0$

Step-by-step explanation:

Hi there!

$\displaystyle\frac{2}{3} (6x+30)=5(x+4)-2x$

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3 years ago

Anyone mind helping me out?

Igoryamba

Answer:

611 square miles

Step-by-step explanation:

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2 years ago

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Step-by-step explanation:

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