let n be the number of times letter be found (1800), p be the success rate (0.068), and q be the failure rate (1 - 0.068 = 0.932)
mean = np = 1800 x 0.068 = 122.4
standard deviation = √(npq) = √(1800 x 0.068 x 0.932) = 10.6807414
You want to compare the square root of 55 using "mental math". Start off by choosing two perfect squares that you can think of that are close to 55.
If you don't know perfect squares then start with the number 2 and multiply it by itself. 2 times 2 equals 4, so 4 is a perfect square.
Take the number 3, multiply it by itself, and so on. Do this for all the numbers until you find two perfect squares that are close to 55.
The two perfect squares closest to 55 are the square roots of 49 and 64. Find the square root of these numbers.
√49 = 7
√64 = 8
Calculate how far 55 is from 49 and 64. 55 is 6 digits away from 49 and 9 digits away from 64.
This means the square root of 55 will be closer to the square root of 49; 7. Since we know that it will be closer to 7, you can put the less than sign for your answer.
√55 < 7.7
(The actual square root of 55 is ~7.4, so we were correct in determining the answer without using a calculator!)
You can take it apart. There are a top and bottom (both the same) right triangle. So you can find the area of that by multiplying 8*6 and divide by two. Then multiply by two because there are 2 triangles.
You are left with three rectangular sides: One 10x10, one 10x6, and one 10x8.
So your whole equation looks like this: A = 2[(8*6)/2]+(10*10)+(10*6)+(10*8)
No, the ratios aren’t equivalent
Answer:
$41,875
<u>Extra</u>
a. $17,250 [($780,000 – $90,000) ÷ 40]
b. $366,000 [$780,000 – ($17,250 × 24 yrs.)]
c. $29,600 [($366,000 – $70,000) ÷ 10 yrs.]
Step-by-step explanation:
Step 1: Determine the cost of the asset
Step 2: Subtract the estimated salvage value of the asset from the cost of the asset to get the total depreciable amount
Step 3: Determine the useful life of the asset
Step 4: Divide the sum of step (2) by the number arrived at in step (3) to get the annual depreciation amount
