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3 years ago

How would the equilibrium change if the temperature were increased in

Mathematics

1 answer:

Sindrei [870]3 years ago

5 0

Answer:

D. The amount of NO2 and SO2 would increase.

Step-by-step explanation:

This is an exothermic reaction as Heat is among the products. Increasing the temperature would lead to more products in the reaction system. In order for the system to annul this change, more reactants would be formed.

The correct option is;

D. The amount of NO2 and SO2 would increase.

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HELP asap plz Solve 2y^2 – 3y = 2

Veseljchak [2.6K]

Your answer is y = -1/2 and y = 2

To solve this quadratic we first need to subtract 2 from both sides to set it equal to 0, which gives us 2y² - 3y - 2 = 0

Then we just need to factorise it:

2y² - 3y - 2 = 0
(2y + 1)(y - 2) = 0

Now we can set each bracket equal to 0 and solve for y:
2y + 1 = 0
2y = -1
y = -1/2

y - 2 = 0
y = 2

I hope this helps! Let me know if you have any questions :)

7 0

3 years ago

Jin tried to evaluate 5 + 2 x 9 step-by-step.

Zigmanuir [339]

Answer:

5 + 2 x 9

Step 1 = 7 x 9

Step 2 = 63

Step-by-step explanation:

= 5 + 2 x 9

= 5 + ( 2 x 9 )

= 5 + 18

= 23

Step 2 = 7 x 9

= 63

Step 3 = 63

C. jin did not make a mistake

Sorry i'm wrong :)

4 0

4 years ago

Thorium -228 is a radioactive substance that decays 50% every 1.9 years. How much of a 50 gram sample will exist after 22.8 year

Evgesh-ka [11]

Answer:

$A=0.0122\ gr$

Step-by-step explanation:

The exponential decrease formula that we must use is:

$A=A_0e^ {-kt}$

Where A is the amount of thorium as a function of time

$A_0$ is the initial amount and k is the decrease rate

We know that initially there are 50 gr and that you decay 50% every 1.9 years.

$A=A_0*0.5=50*0.5 = 25\\\\t=1.9$

$25=50e^ {-k(1.9)}$

We solve the equation for k

$0.5=e^ {-k(1.9)}$

$ln(0.5)=ln(e^ {-k(1.9)})$

$ln(0.5)=-k(1.9)$

$-1.9k=ln(0.5)$

$k=-\frac{ln(0.5)}{1.9}\\\\k=0.3648$

After 22.8 years the amount of thorium that exists is:

$A=50e^ {-0.3648(22.8)}$

$A=0.0122\ gr$

5 0

4 years ago

A company packages its milk powder in cylindrical

Roman55 [17]

Answer:

704 cm²

Step-by-step explanation:

The circumference of the cylindrical container is given by 2πr.

Now, r = radius of the base

If the diameter of the base is 14 cm then the radius will be 7 cm.

So, the circumference = $\frac{2 \times 22 \times 7}{7} =44$ cm.

Now, the label around the surface of the container placed 2 cm from top and bottom.

Therefore, the width of the label is (20 - 2 - 2) = 16 cm and the length is 44 cm.

Hence, the area of each label is (44 × 16) = 704 cm² (Answer)

3 0

4 years ago

1 point

spayn [35]

well, what we do is, simply get the area of the containing rectangle, is an 8x10, and then get the area of the circle, with a radius of half of 4.3 or r = 2.15, and then if we subtract the area of the circle from the rectangle's, what's leftover is the shaded part.

$\stackrel{\textit{\large Areas}}{\stackrel{rectangle's}{(8\cdot 10)}~~-~~\stackrel{circle's}{[\pi (2.15)^2]}}\implies 80-4.6225\pi ~~\approx~~65.5$

5 0

3 years ago