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lana [24]
3 years ago
13

How would the equilibrium change if the temperature were increased in

Mathematics
1 answer:
Sindrei [870]3 years ago
5 0

Answer:

D. The amount of NO2 and SO2 would increase.

Step-by-step explanation:

This is an exothermic reaction as Heat is among the products. Increasing the temperature would lead to more products in the reaction system. In order for the system to annul this change, more reactants would be formed.

The correct option is;

D. The amount of NO2 and SO2 would increase.

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HELP!! Algebra help!! Will give stars thank u so much <333
Anna35 [415]

Answers:

  • Part a)  \bf{\sqrt{x^2+(x^2-3)^2}
  • Part b)  3
  • Part c)   2.24
  • Part d)  1.58

============================================================

Work Shown:

Part (a)

The origin is the point (0,0) which we'll make the first point, so let (x1,y1) = (0,0)

The other point is of the form (x,y) where y = x^2-3. So the point can be stated as (x2,y2) = (x,y). We'll replace y with x^2-3

We apply the distance formula to say...

d = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\\\d = \sqrt{(0-x)^2+(0-y)^2}\\\\d = \sqrt{(0-x)^2+(-y)^2}\\\\d = \sqrt{x^2 + y^2}\\\\d = \sqrt{x^2 + (x^2-3)^2}\\\\

We could expand things out and combine like terms, but that's just extra unneeded work in my opinion.

Saying d = \sqrt{x^2 + (x^2-3)^2} is the same as writing d = sqrt(x^2-(x^2-3)^2)

-------------------------------------------

Part (b)

Plug in x = 0 and you should find the following

d(x) = \sqrt{x^2 + (x^2-3)^2}\\\\d(0) = \sqrt{0^2 + (0^2-3)^2}\\\\d(0) = \sqrt{(-3)^2}\\\\d(0) = \sqrt{9}\\\\d(0) = 3\\\\

This says that the point (x,y) = (0,3) is 3 units away from the origin (0,0).

-------------------------------------------

Part (c)

Repeat for x = 1

d(x) = \sqrt{x^2 + (x^2-3)^2}\\\\d(1) = \sqrt{1^2 + (1^2-3)^2}\\\\d(1) = \sqrt{1 + (1-3)^2}\\\\d(1) = \sqrt{1 + (-2)^2}\\\\d(1) = \sqrt{1 + 4}\\\\d(1) = \sqrt{5}\\\\d(1) \approx 2.23606797749979\\\\d(1) \approx 2.24\\\\

-------------------------------------------

Part (d)

Graph the d(x) function found back in part (a)

Use the minimum function on your graphing calculator to find the lowest point such that x > 0.

See the diagram below. I used GeoGebra to make the graph. Desmos probably has a similar feature (but I'm not entirely sure). If you have a TI83 or TI84, then your calculator has the minimum function feature.

The red point of this diagram is what we're after. That point is approximately (1.58, 1.66)

This means the smallest d can get is d = 1.66 and it happens when x = 1.58 approximately.

6 0
2 years ago
If there are 1,760 yards in 1 mile, how many yards are in 2.5 miles?
Karolina [17]

Answer:

4400 Yards

Step-by-step explanation:

Divide 1760 to get how many yards are in half of a mile

Take the number of yards in one mile and double that and then add the number in half of a mile

8 0
2 years ago
Read 2 more answers
How can you determine which variable is dependent and which variable is independent
padilas [110]

MrBillDoesMath!

Answer:  The dependent variable depends on another variable for its value. For example, if  y = 2x,  setting x = 1 forces y= 2.; setting x = 10, forces y =20.  There are no other possibilities for y once x ids chosen. So y is the dependent variable and x is the independent one. You can pick values for the independent variable (x) but no so for the dependent one.

MrB

8 0
3 years ago
Read 2 more answers
FUNDRAISING A school is raising money by selling calendars for $20 each. Mrs. Hawkins promised a party to whichever of her Engli
____ [38]

Rj, this is the solution to question 19:

• 1st period class sold 60 calendars in total

,

• 2nd period class sold 123 calendars in total

We calculate the average per week, this way:

• 1st period class sold 60/4 = 15 calendars per week

,

• 2nd period class sold 123/4 = 30.75 calendars per week

In consequence the multiplication equation that represents this situation is:

15w + 30.75w = 183, where w is the number of weeks Mrs. Hawkins' classes sold calendars.

This is the solution to question 20:

We already know the average number of calendars that 1st and 2nd period classes sold per week. Now, let's calculate the average for 3nd 4th peiod classes, this way:

• 3rd period class sold 89 calendars in total

,

• 4th period class sold 126 calendars in total

Therefore, the average is:

• 3rd period class sold 89/4 = 22.25 calendars per week

,

• 4th period class sold 126/4 = 31.5 calendars per week

Summarizing, we have:

15 + 30.75 + 22.25 + 31.5 = 99.5 calendars was the average number sold by all her classes in a week.

•

7 0
1 year ago
Help pleaseeee!!!!!!
coldgirl [10]

Answer:

18. 46

19. 0.7

22. 4 3/4

23. 54.5

26. 14

27. 11.5

31. 15

etc.

Step-by-step explanation:

absolute value means that the sign in front of the # doesn't matter, you just have to look at the positive value, for example:

absolute value of 46  =  46

absolute value of - 36 = 36

(imagine the sign in front of the # isn't there)

4 0
3 years ago
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