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2 years ago

Which is the smaller integer : -29 or -10 ?

Mathematics

1 answer:

Helga [31]2 years ago

8 0

Answer:

-29

Step-by-step explanation:

On a number line, negative numbers lie on the left side of zero and positives on the right. The furthest to the right of the number line will be the large number and the furthest to the left will be the smaller. -10 is furthest to the right making it the larger integer and -29 the smallest.

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Help me with trigonometry

poizon [28]

Answer:

See below

Step-by-step explanation:

It has something to do with the Weierstrass substitution, where we have

$\int\, f(\sin(x), \cos(x))dx = \int\, \dfrac{2}{1+t^2}f\left(\dfrac{2t}{1+t^2}, \dfrac{1-t^2}{1+t^2} \right)dt$

First, consider the double angle formula for tangent:

$\tan(2x)= \dfrac{2\tan(x)}{1-\tan^2(x)}$

Therefore,

$\tan\left(2 \cdot\dfrac{x}{2}\right)= \dfrac{2\tan(x/2)}{1-\tan^2(x/2)} = \tan(x)=\dfrac{2t}{1-t^2}$

Once the double angle identity for sine is

$\sin(2x)= \dfrac{2\tan(x)}{1+\tan^2(x)}$

we know $\sin(x)=\dfrac{2t}{1+t^2}$ , but sure, we can derive this formula considering the double angle identity

$\sin(x)= 2\sin\left(\dfrac{x}{2}\right)\cos\left(\dfrac{x}{2}\right)$

Recall

$\sin \arctan t = \dfrac{t}{\sqrt{1 + t^2}} \text{ and } \cos \arctan t = \dfrac{1}{\sqrt{1 + t^2}}$

Thus,

$\sin(x)= 2 \left(\dfrac{t}{\sqrt{1 + t^2}}\right) \left(\dfrac{1}{\sqrt{1 + t^2}}\right) = \dfrac{2t}{1 + t^2}$

Similarly for cosine, consider the double angle identity

Thus,

$\cos(x)= \left(\dfrac{1}{\sqrt{1 + t^2}}\right)^2- \left(\dfrac{t}{\sqrt{1 + t^2}}\right)^2 = \dfrac{1}{t^2+1}-\dfrac{t^2}{t^2+1} =\dfrac{1-t^2}{1+t^2}$

Hence, we showed $\sin(x) \text { and } \cos(x)$

======================================================

$5\cos(x) =12\sin(x) +3, x \in [0, 2\pi ]$

Solving

$5\,\overbrace{\frac{1-t^2}{1+t^2}}^{\cos(x)} = 12\,\overbrace{\frac{2t}{1+t^2}}^{\sin(x)}+3$

$\implies \dfrac{5-5t^2}{1+t^2}= \dfrac{24t}{1+t^2}+3 \implies \dfrac{5-5t^2 -24t}{1+t^2}= 3$

$\implies 5-5t^2-24t=3\left(1+t^2\right) \implies -8t^2-24t+2=0$

$t = \dfrac{-(-24)\pm \sqrt{(-24)^2-4(-8)\cdot 2}}{2(-8)} = \dfrac{24\pm 8\sqrt{10}}{-16} = \dfrac{3\pm \sqrt{10}}{-2}$

$t=-\dfrac{3+\sqrt{10}}{2}\\t=\dfrac{\sqrt{10}-3}{2}$

Just note that

$\tan\left(\dfrac{x}{2}\right) = \dfrac{3\pm 8\sqrt{10}}{-2}$

and $\tan\left(\dfrac{x}{2}\right)$ is not defined for $x=k\pi , k\in\mathbb{Z}$

6 0

2 years ago

Hey, I need help on this assignment

True [87]

Step-by-step explanation:

YO ≅ NZ

Given

YO + OZ ≅ NZ + OZ

Additive property

YZ ≅ NO

Segment addition postulate

∠M ≅ ∠X, ∠N ≅ ∠Y

Given

ΔMNO ≅ ΔXYZ

AAS congruence

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3 years ago

A car travels 2 5/8 miles in 3 1/2minutes at a constant speed. Which equation represents the distance, d, that the car travels i

kakasveta [241]

Answer:

Step-by-step explanation:

2⅝ miles/(3½ minutes) = (21/8 miles)/(7/2 minutes) = ¾ mile/minute

d = ¾m = 0.75m

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2 years ago

Find the measure of the angle.

Finger [1]

Answer:

the awnser should be. 165

5 0

2 years ago

Read 2 more answers

20) Use the distributive property to factor the expression. 10xz − 20yz A) z(10x − 20y) B) 10(xz − 2yz) C) 10z(x − 2y) D) xyz(10

vekshin1

Answer:

The correct answer is C) 10z(x − 2y)

Step-by-step explanation:

To find this, we look for the greatest common factor of those two numbers. Each can be divided by 10 and each have a z. So we divide each term by 10z and put that on the outside of the parenthesis.

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3 years ago