Answer:
yes to both
Step-by-step explanation:
(1) For y=1, and x=a, ...
a² + 1² ≤ 3
-√2 ≤ a ≤ √2 . . . . . subtract 1 and take the square root
All values of "a" are less than 2 inside the circle.
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(2) For y=4 and x=a, ...
2·4 +4·a = 10
4a = 2 . . . . . . . subtract 8
a = 1/2 . . . . . . .divide by 4
The value of "a" for point (a, 4) on the line is less than 2.
The formula we need is this one:
. Filling in accordingly, we have x+4(x+4+1)=x+1(x+1+11). Simplifying that we get (x+4)(x+5)=(x+1)(x+12). We will FOIL both sides to get
. Combining like terms gives us this simplification: 0=4x-8. If we factor out the common 4, we have 0 = 4(x-2). By the Zero Product Property, eitheer 4=0 or x-2=0. Well obviously, 4 does not equal zero, so x-2 = 0, and x = 2.
Answer:
C) 4/15
Step-by-step explanation:
The two equations ...
- 2x + 1/2y = 2
- 1/2x + 2y = 6
can be solved for x using Cramer's rule:
x = (2·2 -1/2·6)/(2·2 -1/2·1/2) = (4-3)/(4-1/4) = 1/(15/4)
x = 4/15
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Cramer's rule for the solution to ...
is ...
- ∆ = ae-db
- x = (ce -fb)/∆
- y = (fa-dc)/∆
Answer:
Step-by-step explanation:
18x-2 = 17x +2
⇒18x-17x - 2 = 2
⇒x - 2 = 2
∴ x = 4
Answer: ??????
Step-by-step explanation:
