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Vadim26 [7]
4 years ago
10

Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118. If a recent test-taker

is selected at random, what is the probability the student scored 691 or greater on the exam ?
Mathematics
1 answer:
suter [353]4 years ago
7 0

Answer:

The probability is 0.06681

Step-by-step explanation:

To calculate this, we need to calculate the standard score or z-score

Mathematically, the standard score can be calculated using the formula;

z-score = (x - mean)/SD

from the question, the mean is 514 and the standard deviation is 118

The z-score is thus = (691-514)/118 = 177/118 = 1.5

The probability we are trying to calculate is thus;

P(x ≥ 691) or P(z ≥ 1.5)

Using standard score table or calculator,

Recall, P( x < 691) = 1 - P( x ≥ 691)

Hence, P( x ≥ 691) = 1 - P( x < 691)

P( x ≥ 691) = 1 - 0.93319

= 0.06681

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Answer:

Given:

Suppose Paul receives a 6% raise every year.

To find:

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The formula used to calculate percentage is: (value/total value)*100%.

Step-by-step explanation:

Step 1 of 1

Assume his salary is originally  100 dollars.

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The function is f(x) = 86(1.01)^7x; grows approximately at a rate of 1% daily

<h3>How to rewrite the function?</h3>

The function is given as:

f(x) = 86(1.08)^x

There are 7 days in a week.

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timurjin [86]
First of all, you have to understand g<span> is a square-root function. 

</span>Square-root functions are continuous across their entire domain, and their domain is all real x-<span>values for which the expression within the square-root is non-negative. 
</span>
In other words, for any square-root function q and any input c in the domain of q (except for its endpoint), we know that this equality holds:  lim \ q(x)=q(c) 

Let's take \sqrt{x} <span>as an example. 
</span>
The domain of \sqrt x is all real numbers such that x \geq 0.  Since x=0  is the endpoint of the domain, the two-sided limit at that point doesn't exist (you can't approach 0 <span>from the left). 
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<span>However, continuity at an endpoint only demands that the one-sided limit is equal to the function's value: 
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lim \  \sqrt{x} =  \sqrt{0} =0 

In conclusion, the equality lim \ q(x)=q(c) holds for any square-root function q and any real number c  in the domain of q e<span>xcept for its endpoint, where the two-sided limit should be replaced with a one-sided limit. </span>

The input x=-3,  is within the domain of g<span>. 
</span>
Therefore, in order to find  lim \ g(x)  we can simply evaluate g at x-3<span>. 
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g(x) 

\sqrt{7x+22} 

\sqrt{7(-3)+22} 

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