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Vadim26 [7]
3 years ago
10

Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118. If a recent test-taker

is selected at random, what is the probability the student scored 691 or greater on the exam ?
Mathematics
1 answer:
suter [353]3 years ago
7 0

Answer:

The probability is 0.06681

Step-by-step explanation:

To calculate this, we need to calculate the standard score or z-score

Mathematically, the standard score can be calculated using the formula;

z-score = (x - mean)/SD

from the question, the mean is 514 and the standard deviation is 118

The z-score is thus = (691-514)/118 = 177/118 = 1.5

The probability we are trying to calculate is thus;

P(x ≥ 691) or P(z ≥ 1.5)

Using standard score table or calculator,

Recall, P( x < 691) = 1 - P( x ≥ 691)

Hence, P( x ≥ 691) = 1 - P( x < 691)

P( x ≥ 691) = 1 - 0.93319

= 0.06681

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there are two <u>angle tickmarks</u>, meaning those two angles are equal, wait a second! if those two angles are equal, that means is an isosceles triangle.

now, in an equilateral triangle, all sides are equal, but also all angles are equal, since the sum of all interior angles is 180°, then each angle is really 60°.

let's notice that angle on the upper-left-corner, is a right-angle, but 60° are on the equilateral triangle, and so the remaining 30° must be on the isosceles triangle.

the isosceles triangle has then a vertex of 30°, and twin angles, the twin angles let's say are each a° so then

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well, we know that y = 75, so the sides with the tickmark are then (75) - 25 = 50 = x.

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Step-by-step explanation:

<h3>Solution:</h3>

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