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Karolina [17]
3 years ago
8

What is the scientific notation of 130400000)

Mathematics
2 answers:
kompoz [17]3 years ago
7 0
That would be 1.304*10 exponent 8 right?!?!
VashaNatasha [74]3 years ago
5 0
Scientific Notation is a number between one and ten times ten to the power of a number. I'll go through the steps below.
1: get a decimal from 130400000 but count the number of times that you move the decimal.
<span>0 - 130400000.
1 - 13040000.0
2 - 1304000.00
3 - 130400.000
4 - 13040.0000
5 - 1304.00000
6 - 130.400000
7 - 13.0400000
<u>8 - 1.30400000
</u>2: So you need to move the decimal 8 times to the left, and you get 1.304! scientific notation is just moving a decimal... sooo...
</span><span><u><em>1.304 X10^8 </em><em /></u>
That is the answer. X10 is used with every scientific notation problem, and 8 is the number of times you'll have to move the exponent to get 130,400,000</span><span />
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Multiply the liters by (0.264 gallon/liter)
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6 0
4 years ago
Simplify this expression 6(a)^0(a)^-2
tamaranim1 [39]

Answer:

6a^-2

Step-by-step explanation:

6(a)^0(a)^-2

= 6(a)^0-2

= 6(a)^-2

3 0
4 years ago
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Deffense [45]
The amount he will have left over is 14. Because there are three pizzas that need 2 cups each. (2x3=6) If he bought a 20 cup bag then he has 14 cups left over. (20-6=14)
5 0
3 years ago
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Rufina [12.5K]

Answer:

f(x)=\dfrac{-50(x-1)(x-2)}{(x-5)(x+5)}

Step-by-step explanation:

Since f(x) has asymptotes at x = 5 and x = -5, then the denominator of the rational function contains the terms (x - 5) and (x + 5):

f(x)=\dfrac{?}{(x-5)(x+5)}

Since f(x) has x-intercepts at x = 2 and x = 1, then the numerator of the rational function contains the terms (x - 2) and (x - 1):

f(x)=\dfrac{A(x-1)(x-2)}{(x-5)(x+5)}

Now substitute the point (0, 4) and solve for A:

f(0)=4\\\\\implies \dfrac{A(0-1)(0-2)}{(0-5)(0+5)}=4\\\\\\\implies -\dfrac{2}{25}A=4\\\\\\\implies A=-50

So final rational function:

f(x)=\dfrac{-50(x-1)(x-2)}{(x-5)(x+5)}

4 0
3 years ago
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chubhunter [2.5K]

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8) 63, 126, 189, 252, 315, 378

4 0
3 years ago
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