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Olin [163]
3 years ago
7

What division problem does this model represent

Mathematics
1 answer:
jeyben [28]3 years ago
7 0
Answer choice B is correct
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Help on this math questions please!
padilas [110]

Answer:

y =  - 3 {x}^{2} ( {x}^{2}  + 8x + 15) =  \\  =- 3 {x}^{2} ( (x + 3)(x + 5))  \\ roots \\ 0 \\  - 3 \\  - 5

6 0
3 years ago
If x = (√2 + 1)^-1/3 then the value of x^3 + 1/x^3 is​
Shtirlitz [24]

Step-by-step explanation:

<u>Given</u><u>:</u> x = {√(2) + 1}^(-1/3)

<u>Asked</u><u>:</u> x³+(1/x³) = ?

<u>Solution</u><u>:</u>

We have, x = {√(2) + 1}^(-1/3)

⇛x = [1/{√(2) + 1}^(1/3)]

[since, (a⁻ⁿ = 1/aⁿ)]

Cubing on both sides, then

⇛(x)³ = [1{/√(2) + 1}^(1/3)]³

⇛(x)³ = [(1)³/{√(2) + 1}^(1/3 *3)]

⇛(x)³ = [(1)³/{√(2) + 1}^(1*3/3)]

⇛(x)³ = [(1)³/{√(2) + 1}^(3/3)]

⇛(x * x * x) = [(1*1*1)/{√(2) + 1)^1]

⇛x³ = [1/{√(2) + 1}]

Here, we see that on RHS, the denominator is √(2)+1. We know that the rationalising factor of √(a)+b = √(a)-b. Therefore, the rationalising factor of √(2)+1 = √(2) - 1. On rationalising the denominator them

⇛x³ = [1/{√(2) + 1}] * [{√(2) - 1}/{√(2) - 1}]

⇛x³ = [1{√(2) + 1}/{√(2) + 1}{√(2) - 1}]

Multiply the numerator with number outside of the bracket with numbers on the bracket.

⇛x³ = [{√(2) + 1}/{√(2) + 1}{√(2) - 1}]

Now, Comparing the denominator on RHS with (a+b)(a-b), we get

  • a = √2
  • b = 1

Using identity (a+b)(a-b) = a² - b², we get

⇛x³ = [{√(2) - 1}/{√(2)² - (1)²}]

⇛x³ = [{√(2) - 1}/{√(2*2) - (1*1)}]

⇛x³ = [{√(2) - 1}/(2-1)]

⇛x³ = [{√(2) - 1}/1]

Therefore, x³ = √(2) - 1 → → →Eqn(1)

Now, 1/x³ = [1/{√(2) - 1]

⇛1/x³ = [1/{√(2) - 1] * [{√(2) + 1}/{√(2) + 1}]

⇛1/x³ = [1{√(2) + 1}/{√(2) - 1}{√(2) + 1}]

⇛1/x³ = {√(2) + 1}/[{√(2) - 1}{√(2) + 1}]

⇛1/x³ = [{√(2) + 1}/{√(2)² - (1)²}]

⇛1/x³ = [{√(2) + 1}/{√(2*2) - (1*1)}]

⇛1/x³ = [{√(2) + 1}/(2-1)]

⇛1/x³ = [{√(2) + 1}/1]

Therefore, 1/x³ = √(2) + 1 → → →Eqn(2)

On adding equation (1) and equation (2), we get

x³ + (1/x³) = √(2) -1 + √(2) + 1

Cancel out -1 and 1 on RHS.

⇛x³ + (1/x³) = √(2) + √(2)

⇛x³ + (1/x³) = 2

Therefore, x³ + (1/x³) = 2

<u>Answer</u><u>:</u> Hence, the required value of x³ + (1/x³) is 2.

Please let me know if you have any other questions.

3 0
2 years ago
Solve for x.<br> 2x + 4<br> 4x - 88<br> x = [?]
baherus [9]
Solve for x.
2x + 4= 8
4x - 88 = -352
x = [?]
7 0
3 years ago
6-
Veseljchak [2.6K]

Answer:

c=45 +679 =6y=8h

Step-by-step explanation:

8 0
3 years ago
Can somebody help me with this?
Juli2301 [7.4K]

Answer:

E) 1/2

Step-by-step explanation:

This is no ordinary problem. It actually requires you to solve two different problems in order to figure out the correct answer.

First, we must figure out what the hypotenuse of the triangle is. We have the two small sides (5 and 12), but don't have the larger side. To find this, we must use the Pythagorean theorem: a^{2} + b^2 =c^2

Let's plug in our a and b values

5^2 + 12^2 = C^2

Simplify

144 + 25 = c^2

169 = c^2

Square both sides

c = 13

But sadly, we aren't done yet. Now we know the length of the whole hypotenuse side. Time to figure out what X is by a simple equation.

12x + 14x = 13

Simplify

26x = 13

Divide by 26

Answer is 1/2

6 0
3 years ago
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