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timama [110]
3 years ago
8

What are three ratios for 5/9

Mathematics
1 answer:
RideAnS [48]3 years ago
8 0
10:18 and 15:27 because whenyou mutiply the numerator and denominatorby any number the answer would be equivalent to 5/9

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#78 please explain work
kenny6666 [7]

Answer:

$0.40c + $0.20h = $11

Step-by-step explanation:

c = chocolate pieces

h = hard candy

$0.40c + $0.20h = $11

5 0
3 years ago
1. 112<br><br> 2. 136 <br><br> 3. 68 <br><br> 4. 158 <br><br> 5. 129
RideAnS [48]

Answer:

4. 158

Step-by-step explanation:

First let's make things a little simpler and put these arcs in terms of x.  We know that the degree measure around the outside of a circle, regardless of its size, is 360.  So let's say that arc BC is x.  That means that arc BDC is 360 - x.  This is because arc BC + arc BDC = 360.  Substituting in our x's we have:

x + 360 - x = 360 and

360 = 360.  (That's just the proof that putting in our x's as we did does in fact work!)

Following the formula then, we have

22=\frac{1}{2}(360-x-x) and

22=\frac{1}{2}(360-2x)

Multiply both sides by 2 to get rid of the fraction and get

44 = 360 - 2x

Subtract 360 rom both sides to get

-316 = -2x

Divide both sides by -2 to get that x = 158

Since we are looking for arc BC and we designated arc BC as our x, that means that arc BC = 158.

3 0
4 years ago
Which statement describes independent events?
Paul [167]
C because drawing the blue marble doesn’t affect drawing the yellow marble because the blue marble was replaced
4 0
1 year ago
Evaluate a+b for a =34 and b=-6
Digiron [165]

Question

evaluate a+b for a =34 and b=-6

a + b =

34 + (-6) =

34 - 6 =

28

5 0
3 years ago
Read 2 more answers
Copy the problems onto your paper, mark the givens and prove the statements asked. Given: ∠BTO ≅ ∠IWE WI ≅ BT , OW ≅ ET Prove: △
Varvara68 [4.7K]

Answer:

\triangle BOT \cong \triangle IEW

Step-by-step explanation:

We are given the following in the question:

\angle BTO \cong \angle IWE\\WI \cong BT\\OT \cong EW

We have to prove:

\triangle BOT \cong \triangle IEW

Proof:

\text{In }\triangle BOT \text{ and } \triangle IEW

we can write:

\angle BTO = \angle IWE\text{ (Given)}\\WI \cong BT\text{ (Given)}\\OT \cong EW\text{ (Given)}

Hence, the two triangle are congruent by SAS congruency rule.

\triangle BOT \cong \triangle IEW

The attached image shows the two triangle.

8 0
3 years ago
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