It would be 56. The LCM of 14 and 8 is 56.
i think one which is where x=-6
The electric field strength at any point from a charged particle is given by E = kq/r^2 and we can use this to calculate the field strength of the two fields individually at the midpoint.
The field strength at midway (r = 0.171/2 = 0.0885 m) for particle 1 is E = (8.99x10^9)(-1* 10^-7)/(0.0885)^2 = -7.041 N/C and the field strength at midway for particle 2 is E = (8.99x10^9)(5.98* 10^-7)/(0.0935)^2 = <span>-7.041 N/C
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Note the sign of the field for particle 1 is negative so this is attractive for a test charge whereas for particle 2 it is positive therefore their equal magnitudes will add to give the magnitude of the net field, 2*<span>7.041 N/C </span>= 14.082 N/C
Answer:
The answer is
<h2>
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Step-by-step explanation:
To find an equation of a line when given the slope and a point we use the formula
where
m is the slope
( x1 , y1) is the point
From the question the point is (5, -6) and slope - 3/5
The equation of the line is
We have the final answer as
Hope this helps you
Answer:
61-4g
Step-by-step explanation:
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