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Alinara [238K]
3 years ago
11

Write a Linear question that has a point that goes through (2,-4) and parallel to y=3x+2

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
6 0

Answer:

Y=3x-6

Step-by-step explanation:

You use the point-slope form formula.

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can sumone just do number 17 for me thats it, ill give brainlist if correct and plz dont spam me or perposly answer knowing you
rusak2 [61]

Answer: For 17 is x=24

Step-by-step explanation:

5 0
3 years ago
3-(x-1)=-1-(5-x) pls help
Alika [10]

Answer:

- 3(x - 1) =  - 1(5 - x) \\  \\ 3 - x + 1 =  - 5 + x \\  \\  - x - x =  - 5 - 3 - 1 \\  \\  - 2x =  - 5 - 3 - 1 \\  \\  - 2x =   - 9 \\  \\ x =  \frac{ - 9}{ - 2}  \\  \\ x = 4.5

3 0
3 years ago
Simplify: 16z8-23z8 <br><br>enter the original expression if it can't be simplified
inn [45]

Answer:

The simplified version of that equation would be -7z^{8}.

Step-by-step explanation:

Since 16z^{8} and 23z^{8} have the same exponent and variable, we can combine them normally.


16z^{8} - 23z^{8} =  -7z^{8}

4 0
4 years ago
The base of a triangle exceeds the height by 9 centimeters. If the area is 56 square centimeters, find the length of the base an
shepuryov [24]

Answer:

The height of the triangle is 7cm and the base is 16cm

Step-by-step explanation:

First of all we have to know the formula to calculate area of ​​a triangle

a = area = 56

b = base

h = heigth

a = (b * h)/2

we replace the known values and we make 2 equations

56cm² = (b * h)/2

b = h + 9cm

we replace b by (h + 9cm) in the first equation

56cm² = (h + 9cm * h)/2

56cm² * 2 = h² + 9h

0 = h² + 9h - 112cm²

we use bhaskara formula:

(-b (±) √ (b² - 4ac) ) / 2a

we replace with the known values

h = (-9 (±) √ (9² - 4*1*(-112) ) ) / 2*1

h = (-9 (±) √ (81 + 448) ) ) / 2

h = (-9 (±) √529) /2

h = (-9 (±) 23)/2

h1 = (-9 + 23) / 2

h1 = 14 / 2

h1 = 7

h2 = (-9 - 23) / 2

h2 = -32 / 2

h2 = -16

The height of the triangle is 7cm and the base is 16cm

8 0
3 years ago
Figure ABCDE is similar to figure VWXYZ.
topjm [15]
D would be the answer to your question
4 0
3 years ago
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