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3 years ago

Simplify: 16z8-23z8 enter the original expression if it can't be simplified

Mathematics

1 answer:

inn [45]3 years ago

4 0

Answer:

The simplified version of that equation would be $-7z^{8}$ .

Step-by-step explanation:

Since $16z^{8}$ and $23z^{8}$ have the same exponent and variable, we can combine them normally.

$16z^{8}$ - $23z^{8}$ = $-7z^{8}$

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) a water tank is emptying steadily by 2 liters of water per hour. there were 2 liters of water 6 hours after midnight. let x re

REY [17]

First of all, let's find the water tank total amount
according to the exercice, there were 2 L (L =liters) of water at 6 am (6hours after midnight ).
Consider T as total amount of water
so we have
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2 years ago

Y=−1/3x+4 Then plot two points to graph the equation.

Svetlanka [38]

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2 years ago

Find the square. (1/4A + 1/4B)^2 a) 1/16A^2 + 1/8AB + 1/16B^2 b) 1/4A^2 + 1/8AB + 1/4B^2

alisha [4.7K]

$(a + b)^2 = a^2 + 2ab + b^2$

$(\dfrac{1}{4}A + \dfrac{1}{4}B)^2 =$

$= \dfrac{1}{16}A^2 + \dfrac{1}{8}AB + \dfrac{1}{16}B^2$

Answer: A.

Another way to solve by factoring 1/4.

$(\dfrac{1}{4}A + \dfrac{1}{4}B)^2 =$

$= [\dfrac{1}{4}(A + B)]^2$

$= (\dfrac{1}{4})^2(A + B)^2$

$= \dfrac{1}{16}(A^2 + 2AB + B^2)$

$= \dfrac{1}{16}A^2 + \dfrac{1}{16}2AB + \dfrac{1}{16}B)^2$

$= \dfrac{1}{16}A^2 + \dfrac{1}{8}AB + \dfrac{1}{16}B)^2$

6 0

3 years ago

Read 2 more answers

The endpoints of EF are E(1,3) and F(-2,8). Find EF.

Phantasy [73]

Answer:

EF = $\sqrt{34}$ ≈ 5.83

Step-by-step explanation:

Calculate EF using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = E(1, 3) and (x₂, y₂ ) = F(- 2, 8)

EF = $\sqrt{(-2-1)^2+(8-3)^2}$

= $\sqrt{(-3)^2+5^2}$

= $\sqrt{9+25}$

= $\sqrt{34}$ ≈ 5.83 ( to 2 dec. places )

8 0

2 years ago

How do you know if a graph you are looking at shows a periodic function?

Savatey [412]

You know when it is a periodic function if the values repeats in regular intervals or periods. An example of this is trigonometric functions that repeat over intervals of 2 pi radians.

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2 years ago