Answer:
What is it you need help with?
Step-by-step explanation:
Which one
Answer: what now sorry don’t know
Step-by-step explanation:
Complete question :
The GPAs of all students enrolled at a large university have an approximately normal distribution with a mean of 3.02 and a standard deviation of .29.Find the probability that the mean GPA of a random sample of 20 students selected from this university is 3.10 or higher.
Answer:
0.10868
Step-by-step explanation:
Given that :
Mean (m) = 3.02
Standard deviation (s) = 0.29
Sample size (n) = 20
Probability of 3.10 GPA or higher
P(x ≥ 3.10)
Applying the relation to obtain the standardized score (Z) :
Z = (x - m) / s /√n
Z = (3.10 - 3.02) / 0.29 / √20
Z = 0.08 / 0.0648459
Z = 1.2336940
p(Z ≥ 1.2336) = 0.10868 ( Z probability calculator)
Answer:
4 hours and 10 min
Step-by-step explanation:
For this equation we will do ratios:
250 min =
4 hours and 10 min
4(60) = 240
240 + 10 = 250 minutes
So, in order to find out which ordered pairs are the solutions to the given inequality above, we just have to plug in the given values.
Lets take option A.
2 > -3(0) + 2
2 > 0 + 2
2 > 2 ---- 2 is not greater than 2, which makes this ordered pair not a solution to the given inequality.
So, do the same with the rest of the ordered pairs.
So the ordered pairs that are the solutions would only be options C, E and F. Hope that answer helps.
