Answer:
d.4/12
Step-by-step explanation:
Step-by-step explanation:
add up both equations
2x -y + 3x + y -13 = 0 (y will eliminate -y)
5x -13 = 0
5x = 13
x = 13/5 now use this value to find y
2 × 13/5 -y - 4 = 0
26/5 - y -4 = 0
26/5 - 4 = y
6/5 = y
The maximum value of the function y= -3+4 cos(5pi/6(x+4)) can be determined by differentiating the equation then make the derived function equal to zero. In this case, the function becomes 4 sin (5pi/6(x+4)) * (5pi/6) or equal to 10pi/3 sin (5pi/6(x+4)) = 0. sin -1 of 0 is equal to zero. hence, 5pi/6(x+4) should be zero. x is equal to -4. substituting -4 in the original equation,<span>y= -3+4 cos(5pi/6(-4+4)) is equal to 1. The maximum value is 1. </span>
Answer:
We are given that Commercial aircraft used for flying in instrument conditions are required to have two independent radios instead of one.
The probability of failure of one radio = 0.0026
So, the probability of failure of both radio =
Now we are supposed to find the probability that a particular flight will be safe with at least one working radio
A) the probability that a particular flight will be safe with at least one working radio = 1- 0.00000676=0.99999324
B)The usual rounding rule of three significant digits not work here because usual rounding rule of three significant digits makes it 1 which means that both radios are working properly.
C)Yes,this probability is high enough to ensure flight safety because it is close to 1