Yea so whats the question or is that just a fact<span />
I believe the answer is 4 points. Hope this helps!
Answer:
False
Step-by-step explanation:
We first write the equation in the form ax² + bx + c=0 which gives us:
3x² - 6x + 9=0
Given the quadratic formula,
x= [-b ±√(b²- 4ac)]/2a ,the discriminant proves whether the equation has real roots or not.
The discriminant, which is the value under the root sign, may either be positive, negative or zero.
Positive discriminant- the equation has two real roots
Negative discriminant- the equation has no real roots
Zero discriminant - The equation has two repeated roots.
In the provided equation, b²-4ac results into:
(-6)²- (4×3×9)
=36-108
= -72
The result is negative therefore the equation has no real solutions.
<span>let n+2=u
so, the equation became= [2/u]-[3/u]=5
=> [(2+3)/u]=5
=> 5/u=5
=> u=5/5=1
thus, u=1
we know u=n+2
so, n+2=1
=> n=1-2=-1
so, n=-1</span>
Answer: x=3
Step-by-step explanation: Step 1: Simplify both sides of the equation.
21x−5=7+17x
21x+−5=7+17x
21x−5=17x+7
Step 2: Subtract 17x from both sides.
21x−5−17x=17x+7−17x
4x−5=7
Step 3: Add 5 to both sides.
4x−5+5=7+5
4x=12
Step 4: Divide both sides by 4.
= 
So Final Answer: <u>x=3</u>
<u />
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