The solution is....................
F=\dfrac{9}{5}C+32\\\\A.\\\dfrac{9}{5}C+32=F\ \ \ |-32\\\\\dfrac{9}{5}C=F-32\ \ \ |\cdot\dfrac{5}{9}\\\\C=\dfrac{5}{9}(F-32)
B.\\F=212\to C=\dfrac{5}{9}(212-32)=\dfrac{5}{9}\cdot180=100\\\\212^oF=100^oC
C.\\F=80\to C=\dfrac{5}{9}(80-32)=\dfrac{5}{9}\cdot48\approx26.7\\\\80^oF\approx26.7^oC
Answer:
q is less than or equal to 30.5
Step-by-step explanation:
Divide both sides by -3, but change the sign (bc you're dividing by a negative)
120/210 = 0.57
0.57 x 60 = 34.2
34 hours and 12 minutes
The magnitude of the vector is √(7^2+12^2)=√(49+144)=√193
The direction is α=arctan(y/x)=arctan(12/-7)≈-59.74 however this is relative to the negative x-axis so we add 180° to get the standard angle...180-59.74=120.26°
So the vector is √193 @ 120.26°
