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Tems11 [23]
4 years ago
14

Plz help !!!!!!!!!!!!

Mathematics
1 answer:
ValentinkaMS [17]4 years ago
4 0

Answer: \bold{y\sqrt[3]{x}}

<u>Step-by-step explanation:</u>

\sqrt[6]{x^2y^6} =x^{\frac{2}{6}}y^{\frac{6}{6}}=x^{\frac{1}{3}}y=\boxed{y\sqrt[3]{x} }

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How to find angle acb
Crazy boy [7]

Answer:

pls provide the diagram

4 0
4 years ago
Find the value of the variable and DF if D is between C and F if CD 4y -9, DF 2y-7, and CF 14.
Yuri [45]
CF = CD + DF (since D is simply a point on the line, and C to that point added onto F to that point is CF), so 4y-9+2y-7=14. Adding it up, we get 6y-16=14 and adding by 16 we get 30=6y. Dividing both sides by 6, we get y=5. Plugging that into DF, we get 10-7=DF=3
4 0
3 years ago
Which set of side lengths or angle measures can be used to construct a triangle A. 50 inches, 90 inches, 35 inches B. 60 inches,
kolbaska11 [484]

Answer:

D. 60, 45,75

Step-by-step explanation:

For options C and D

For a triangle the sum of the angles must always be equal to 180 degrees

So 180 ≠45+45+80

and

60 +45+ 75= 180

For option A and B

The length of the longer side is equal to the square root of the sum of squares of the other two sides in a triangle.

According to Pythagorus theorem

hypotenuse²= base² + perpendicular²

c²= a²+ b²

90²= 50² + 35²

8100= 2500+1225

8100≠3725

95²= 60²+ 25²

9025= 3600+ 625

9025≠4225

Therefore only D is the correct option

8 0
3 years ago
I'm stuck on this one! Help please?
zepelin [54]
Expand 

(4a + 12 = 12 + 4a)

Cancel 4a on both sides

12 = 12

Since both sides are equal there are infinitely many solutions

Process of elimination, cross out d) no solution. But I would best go with C)
7 0
4 years ago
A rectangle has length 72 cm and width 56 cm. The other rectangle has the same area as this one, but its width is 21 cm. What is
Ira Lisetskai [31]

The length of the rectangle is = 72 cm

The width of the rectangle is = 56 cm

Area of the rectangle is = length*width

= 72\times56=4032 cm²

As given, the other rectangle has the same area as this one, but its width is 21 cm.

Let the length here be = x

4032=x*21

x=\frac{4032}{21}=192

Hence, length is 192 cm.

We can see that as width decreases, the length increases if area is constant and when length decreases then width increases if area is constant.

So, in the new rectangle,constant of variation=k is given by,

\frac{192}{72}=\frac{8}{3} or \frac{56}{21}=\frac{8}{3}

Hence, the constant of variation is \frac{8}{3}

7 0
3 years ago
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