Rewrite the given equation as
.
Since
, you can conclude that the imimum value of y will be gained for the minimum value of
. The minimum value of
is 0 for x=2.
So, y(2)=0+4=4.
Answer: minimum value of y is 4, when x=2.
Answer:
Angle y and Angle x are complementary angles
Step-by-step explanation:
we know that
If
sin(y°)=cos(x°)
then
Angle y and Angle x are complementary angles
so
∠y+∠x=90°
∠x=90°-∠y
sin(y°)=cos(90°-y°)
therefore
The sine of an angle is equal to the cosine of its complementary angle
If you're working with complex numbers, then I'm sure you're comfortable with plotting them on a complex-plane ... real part of the number along the x-axis, and imaginary part of the number along the y-axis.
When you look at it that way, your two points are simply two points on the x-y plane:
4 - i ===> (4, -1)
-2 + 3i ===> (-2, 3) .
The distance between them is
D = √ (difference in 'x')² + (difference in 'y')²
= √ (6)² + (4)²
= √ (36 + 16)
= √ (52)
= 7.211 (rounded)
Given:Price of one taco = x; price of 2 tacos = 2xPrice of salad = $2.50Sales tax = 8% of the combined price of two tacos and a salad, namely .08(2x + 2.50)Tip = constant fee = $3.00Total bill = $13.80 Therefore the equation becomes
2x + 2.50 + .08(2x + 2.50) + 3 = 13.80 Solutions: 2x + 2.50 + .16x + .20 + 3 = 13.80 (using the distributive property to multiply 2x and 2.5 by .08).2.16x + 2.70 + 3 = 13.80 (combining like terms)2.16x + 5.70 = 13.80 (combining like terms)2.16x + 5.70 = 13.80 - 5.70 (subtraction property of equality)2.16x = 8.10x = 8.10/2.16 = 3.75 (division property of equality)
The cost of a single taco is $3.75
Answer: The equilibrium point represents the raising or lowering the price in response to changes in the supply or demand.
If the price of a good is above equilibrium, this means that the quantity of the good supplied exceeds the quantity of the good demanded.
If the quantity is below the equilibrium point, it will create a shortage. because the quantity supplied is less than quantity demanded.
Hope this helps!
Step-by-step explanation:
