0.5 x 1/10 = 0.05 All you do is multiply
Answer:
Side-Side-Side (SSS) Congruence Property
Step-by-step explanation:
Congruence just means that two things are of the same size. For instance, if you have two congruent side lengths, they are the same length. In this picture, you can see that both triangles have a side with one dash and a side with two dashes. In geometry, to show that two lines are congruent you give them the same number of dashes, and therefore you know for sure that those two pairs of sides are congruent. Finally, the triangles share a side length, so you know that that side length is equal for them. Therefore, the appropriate congruence property here is SSS, since you know that three pairs of sides are congruent.
Answer:
Lisa will need
of wood framing
Step-by-step explanation:
we know that
The perimeter of rectangle is equal to
![P=2(b+h)](https://tex.z-dn.net/?f=P%3D2%28b%2Bh%29)
In this problem we have
![b=43.5\ cm](https://tex.z-dn.net/?f=b%3D43.5%5C%20cm)
![h=934\ mm](https://tex.z-dn.net/?f=h%3D934%5C%20mm)
convert to cm
Remember that ![1\ cm=10\ mm](https://tex.z-dn.net/?f=1%5C%20cm%3D10%5C%20mm)
![h=934\ mm=934/10=93.4\ cm](https://tex.z-dn.net/?f=h%3D934%5C%20mm%3D934%2F10%3D93.4%5C%20cm)
substitute the values and solve the perimeter
![P=2(43.5+93.4)=273.8\ cm](https://tex.z-dn.net/?f=P%3D2%2843.5%2B93.4%29%3D273.8%5C%20cm)
Answer:
Option B. (x+3) ^2+(y+4)^2=25
Step-by-step explanation:
we know that
The equation of the circle in standard form is equal to
![(x-h)^{2}+(y-k)^{2}=r^{2}](https://tex.z-dn.net/?f=%28x-h%29%5E%7B2%7D%2B%28y-k%29%5E%7B2%7D%3Dr%5E%7B2%7D)
where
(h,k) is the center and r is the radius
step 1
Find the radius of the circle
Remember that the distance of the center and any point on the circle is equal to the radius of the circle
so
Find the distance between the points (-3,-4) and (0,0)
the formula to calculate the distance between two points is equal to
![d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28y2-y1%29%5E%7B2%7D%2B%28x2-x1%29%5E%7B2%7D%7D)
substitute
![r=\sqrt{(0+4)^{2}+(0+3)^{2}}](https://tex.z-dn.net/?f=r%3D%5Csqrt%7B%280%2B4%29%5E%7B2%7D%2B%280%2B3%29%5E%7B2%7D%7D)
![r=\sqrt{(4)^{2}+(3)^{2}}](https://tex.z-dn.net/?f=r%3D%5Csqrt%7B%284%29%5E%7B2%7D%2B%283%29%5E%7B2%7D%7D)
![r=\sqrt{25}](https://tex.z-dn.net/?f=r%3D%5Csqrt%7B25%7D)
![r=5\ units](https://tex.z-dn.net/?f=r%3D5%5C%20units)
step 2
Find the equation of the circle
![(x-h)^{2}+(y-k)^{2}=r^{2}](https://tex.z-dn.net/?f=%28x-h%29%5E%7B2%7D%2B%28y-k%29%5E%7B2%7D%3Dr%5E%7B2%7D)
the center is the point (-3,-4) and the radius is r=5 units
substitute
![(x+3)^{2}+(y+4)^{2}=5^{2}](https://tex.z-dn.net/?f=%28x%2B3%29%5E%7B2%7D%2B%28y%2B4%29%5E%7B2%7D%3D5%5E%7B2%7D)
![(x+3)^{2}+(y+4)^{2}=25](https://tex.z-dn.net/?f=%28x%2B3%29%5E%7B2%7D%2B%28y%2B4%29%5E%7B2%7D%3D25)
Answer:
This isn't that specific enough
Step-by-step explanation: