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3 years ago

How to find the measure of a triangle?

Mathematics

2 answers:

gulaghasi [49]3 years ago

8 0

Is it 1/2×b×h
to find the area
or
base×height

AleksAgata [21]3 years ago

6 0

Hi there! :)

Answer:

The answer is D. 83°

Step-by-step explanation:

You should know that the interior angles of a triangle always add up to 180°.

So, what you will need to do, is add all 3 angles together and create an equation (equal to 180). Then you need to solve this equation by isolating "x":

(8x + 12) + (55 - 3x) + (10x + 23) = 180

Get rid of all the parentheses

8x + 12 + 55 - 3x + 10x + 23 = 180

Add all similar terms together

8x - 3x + 10x = 15x

12 + 55 + 23 = 90

15x + 90 = 180

Subtract "90" from each side of the equation → 180 - 90 = 90

15x = 90

Divide each side of the equation by "15" → 90 ÷ 15 = 6

x = 6

Since you now know that the value of "x" is 6, you can now find the measure of the angle at George's position by replacing the "x" by 6:

10x + 23 = Measure of the angle at George's position

10(6) + 23

Multiply 10 by 6 → 10 × 6 = 60

60 + 23

Add 60 and 23 together → 60 + 23 = 83

83 = Measure of the angle at George's position

There you go! I really hope this helped, if there's anything just let me know! :)

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A manager of a grocery store wants to determine if consumers are spending

ololo11 [35]

Answer:

1. The error in the assumption is taking the sample mean, $\bar x$ , as being equal to the population mean, μ

2. To correct the error, the manager will need to generate the confidence interval based on the population standard deviation on the acceptable values of the mean using the following relation;

$CI=\bar{x}\pm z\frac{\sigma}{\sqrt{n}}$

Step-by-step explanation:

We note that from the central limit theorem as the size of the sample, n, becomes more and more larger, the mean of the sample, $\bar x$ , approaches that of the population mean, μ, therefore as the grocery store manager uses the sample mean as the population mean's point estimate an error will be observed based on the size of the sample compared to the population, where the difference between the two means (the population mean and the sample mean) is $\left | \bar{x} - \mu \right |$

1. The error in the assumption is taking the sample mean, $\bar x$ , as being equal to the population mean, μ

2. To correct the error, the manager will need to generate the confidence interval based on the population standard deviation on the acceptable values of the mean using the following relation;

$CI=\bar{x}\pm z\frac{\sigma}{\sqrt{n}}$

Where:

σ = Population standard deviation = $30

z = z value at 95% confidence level = 1.96

$\bar x$ = Sample mean $160

n = Sample size = 10

Plugging in the values, we have;

$141.4 < $\bar x$ < $178.6

Hence the expected value of the mean should be between $141.4 and $178.6.

7 0

3 years ago

Evaluate twenty-five minus three x for x equals zero, one, two, three, and four. Which of the following correctly describes the

laiz [17]

Answer:

You take turns plugging in each number for your answers. I’ll list them below.

6(0) - (0)2 = 0

6(1) - (1)2 = 4

6(2) - (2)2 = 8

6(3) - (3)2 = 12

6(4) - (4)2 = 16

6(5) - (5)2 = 20

6(6) - (6)2 = 24

The pattern I’ve noticed is every time you increase the value from the previous meaning for x, the solution increases by 4. I hope this helps and let me know if I’m right.

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3 years ago

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Which function is the inverse of ? f(x)=50,000(0.8)^x

IrinaK [193]

Answer:

y=log(x)−log(50000)log(0.8)

Explanation:

write as : y=50000(0.8)x

Taking logs:

log(y)=log(50000)+log(.(0.8)x.)

But log(.(0.8)x.) is the same as xlog(0.8)

Thus
x=log(y)−log(50000)log(0.8)

Now swap the x'x and the y's giving:

y=log(x)−log(50000)log(0.8)

my teacher helped a little bit

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3 years ago

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Bogdan [553]

Answer:

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Step-by-step explanation:

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3 years ago

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Marizza181 [45]

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