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Alik [6]
3 years ago
9

How to find the measure of a triangle?

Mathematics
2 answers:
gulaghasi [49]3 years ago
8 0
Is it 1/2×b×h
to find the area
or
base×height
AleksAgata [21]3 years ago
6 0

Hi there! :)

<u>Answer:</u>

The answer is <u>D. 83°</u>


Step-by-step explanation:

You should know that the interior angles of a triangle always add up to 180°.

So, what you will need to do, is add all 3 angles together and create an equation (equal to 180). Then you need to solve this equation by isolating "x":

(8x + 12) + (55 - 3x) + (10x + 23) = 180

Get rid of all the parentheses

8x + 12 + 55 - 3x + 10x + 23 = 180

Add all similar terms together

8x - 3x + 10x = <u>15x</u>

12 + 55 + 23 = <u>90</u>

15x <u>+ 90</u> = 180

Subtract "90" from each side of the equation → 180 - 90 = 90

<u>15</u>x = 90

Divide each side of the equation by "15" → 90 ÷ 15 = 6

<u>x = 6</u>


Since you now know that the value of "x" is 6, you can now find the measure of the angle at George's position by replacing the "x" by 6:

10x + 23 = Measure of the angle at George's position

<u>10(6)</u> + 23

Multiply 10 by 6 → 10 × 6 = 60

<u>60 + 23</u>

Add 60 and 23 together → 60 + 23 = 83

<u>83</u> = Measure of the angle at George's position


There you go! I really hope this helped, if there's anything just let me know! :)

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<h3>The distance between two landmarks is 123 meters</h3>

<em><u>Solution:</u></em>

We have to find the distance between two landmarks

<em><u>Use the law of cosines</u></em>

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c^2 = a^2 + b^2 - 2ab\ cos c

Here, angle between 90 meters and 130 meters is 65 degrees

From figure,

a = 90

b = 130

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Therefore,

d^2 = 90^2 + 130^2 - 2(90)(130)\ cos 65\\\\d^2 = 8100 + 16900 - 23400\ cos\ 65\\\\d^2 = 25000 - 23400 \times 0.4226\\\\d^2 = 25000 - 9889.267\\\\d^2 = 15110.73\\\\d = 122.92\\\\d \approx 123

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3 years ago
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Maru [420]

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Step-by-step explanation:

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2 years ago
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Step-by-step explanation:

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7 0
3 years ago
(secx)dy/dx=e^(y+sinx), please help me solve the differential equation. Thanks :)
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