Tacos and tequila baked potato’s chicken beef chorizo
Solution:
The permutation formula is expressed as

The combination formula is expressed as

where

Given that 6 objects are taken at a time from 8, this implies that

Thus,
Number of permuations:

Number of combinations:

Hence, there are 28 combinations and 20160 permutations.
Answer:
Fraction : 3/9
Decimal : 0.33333333 (the .3 continues)
Percent : 33.33333%
Step-by-step explanation:
Dividing 3 by 9 will give you a continous set of 3.
Answer:
C. Decreases the margin of error and hence increases the precision
Step-by-step explanation:
If we select a sample by Simple Random Sampling in a population of “infinite” size (a population so large that we do not know its size exactly), then the margin of error is given by
where
<em>Z = The Z-score corresponding to the confidence level
</em>
<em>S = The estimated standard deviation of the population
</em>
<em>n = the size of the sample.
</em>
As we can see, since n is in the denominator of the fraction and the numerator is kept constant, the larger the sample size the smaller the margin of error, so the correct choice is:
C. Decreases the margin of error and hence increases the precision