Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
Answer:
13
Step-by-step explanation:
Using Pythagoras Theorem:
Substitute values of a and b:
The length of the missing side is 13.
12•1
13•6
12/78 divide both numbers by 6 to simplify
Answer- 2/13
Answer:
B.)58?
Step-by-step explanation:
Hope I helped..
The rate of change is equal to rise over run
= (-1 - 8)÷(3 - 0)
= -9 ÷ 3
= -3
When you say initial value I'm assuming you mean the y-intercept
In that case you first need to find the equation of the line by substituting the gradient and point into the gradient intercept formula
y - 8 = -3(x - 0)
y = -3x + 8
The y-intercept is when x = 0 so,
y = -3(0) + 8
Therefore y = 8
