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2 years ago

7

WRITE AND SOLVE A DIVISON EQUATION TO FIND THE NUMBER OF 1/3 POUND HAMBURGER PATTIES THAT CAN BE MADE 4 POUNDS OF GROUND BEEF.

1 answer:

Musya8 [376]2 years ago

4 0

Answer:

12 patties

Step-by-step explanation:

4 ÷ 1/3 = 12

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$3000 is invested at 3% annual interest for 3 years.<br> a. Simple Interest b. Compound Interest

stich3 [128]

Answer:

a. $270

b. $3,278.18

Step-by-step explanation:

Given that

The principal amount is $3,000

Annual rate of interest is 3%

And, the time period is 3 years

We need to find out the simple interest & compound interest

The following formulas should be used

a. For simple interest

= Principal × rate of interest × time period

= $3,000 × 3% × 3 years

= $270

b. For compound interest

= Principal × (1 + rate of interest)^time period

= $3,000 × (1 + 0.03)3

= $3,000 × 1.03^3

= $3,278.18

8 0

2 years ago

An accountant invested $5000 at a simple interest rate of 8% for 2 years. What total amount of money will she have from her inve

il63 [147K]

Answer:

$5800 plz give the brainliest

Step-by-step explanation:

you have to muliyiply everything so 5000*.08*2 which is 800 now add that to 5000 because thats the amount she put in so it will be $5800.

6 0

2 years ago

Triangle ABC is a right triangle. Triangle A'B'C' has a hypotenuse of 10 after triangle ABC undergoes a dilation of 2. If triang

Mice21 [21]

B) the answer is B three

8 0

3 years ago

solve the given matrix equation for X. Simplify your answers as much as possible. (In the words of Albert Einstein, "Everything

vova2212 [387]

a.

$XA^{-1}=A^3$

$(XA^{-1})A=A^3A$

$X(A^{-1}A)=A^4$

$X=A^4$

b.

$AXB=(BA)^2$

$A^{-1}(AXB)B^{-1}=A^{-1}(BA)^2B^{-1}$

$(A^{-1}A)X(BB^{-1})=A^{-1}(BA)^2B^{-1}$

$X=A^{-1}(BA)^2B^{-1}$

c.

$(A^{-1}X)^{-1}=(AB^{-1})^{-1}(AB^2)$

$X^{-1}A=(BA^{-1})(AB^2)$

$X^{-1}A=B(A^{-1}A)B^2$

$X^{-1}A=B^3$

$(XX^{-1})A=XB^3$

$XB^3=A$

$X(B^3(B^3)^{-1})=A(B^3)^{-1}$

$X=A(B^3)^{-1}$

d. Not totally sure what the equation is supposed to be, but I guess it's

$ABXA^{-1}B^{-1}=A$

$ABX(BA)^{-1}=A$

$((AB)^{-1}(AB))X((BA)^{-1}(BA))=(AB)^{-1}A(BA)$

$X=(AB)^{-1}A(BA)$

$X=(B^{-1}A^{-1})A(BA)$

$X=B^{-1}(A^{-1}A)(BA)$

$X=(B^{-1}B)A$

$X=A$

7 0

3 years ago

How do you do this I really need some help!please

Rzqust [24]

Answer:

It is correct for 5. Incorrect for 6. Lastly, correct for 7.

5 0

2 years ago

Read 2 more answers