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ella [17]
2 years ago
7

WRITE AND SOLVE A DIVISON EQUATION TO FIND THE NUMBER OF 1/3 POUND HAMBURGER PATTIES THAT CAN BE MADE 4 POUNDS OF GROUND BEEF.

Mathematics
1 answer:
Musya8 [376]2 years ago
4 0

Answer:

12 patties

Step-by-step explanation:

4 ÷ 1/3 = 12

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The advertised size of a computer or television screen is actually the length of the diagonal of
andreyandreev [35.5K]

Answer:

37.5 cm

Step-by-step explanation:

See attached for reference.

let the diagonal be x,

By Pythagorean formula:

x² = (22.5)² + (30)²

x = √[(22.5)² + (30)²]

x = 37.5 cm

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I trying to simplify ( 14+5) +15÷2 PLEASE HELP this is a 5th grade math question
sertanlavr [38]

Answer:

14+5 = 19

19 + 15/2

15/2 = 7.5

19+7.5 = 26.5


Just remember PEMDAS!

Pls mark brainliest

Step-by-step explanation:


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3 years ago
McKenzie bought 1.2 pounds of coffee for $11.82. What was the cost per pound?
Viktor [21]
The answer to that is 9.85
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Max puts a stopper in the bathtub and turns on the faucet at t = 0.
Marysya12 [62]

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New legislation passed in 2017 by the U.S. Congress changed tax laws that affect how many people file their taxes in 2018 and be
stiks02 [169]

Answer:

a. Yes

b. 0.35

c. 0.5

d.

E(x)=34.25

V(x)=73.1875

SD(x)=8.555

Step-by-step explanation:

a.

x      20   25   30      35   40  45 50

f(x) 0.05 0.2 0.25  0.15  0.15 0.1 0.1

This will be valid probability distribution if

1. All probabilities are between 0 and 1 inclusive.

2. Sum of probabilities must be 1.

Condition 1 is satisfied in this distribution. Now, we will check second condition

sum(f(x))=0.05+0.2+0.25+0.15+0.15+0.1+0.1=1.

As the both conditions are satisfied, thus the given distribution is a valid probability distribution.

b.

P(x≥40)=P(X=40)+P(X=45)+P(X=50)

P(x≥40)=0.15+0.1+0.1

P(x≥40)=0.35

So, the probability that Backens and Hayes LLC will obtain 40 or more new clients is 0.35.

c.

P(x<35)=P(X=20)+P(X=25)+P(X=30)

P(x<35)=0.05+0.2+0.25

P(x<35)=0.5

So, the probability that Backens and Hayes LLC will obtain fewer than 35 new clients is 0.5.

d.

Expected value of x=E(x)= sum[x*f(x)]

E(x)= 20*0.05+25*0.2+30*0.25+35*0.15+40*0.15+45*0.1+50*0.1

E(x)=1+5+7.5+5.25+6+4.5+5

E(x)=34.25

Variance of x=V(x)=sum[x²*f(x)]-(sum[x*f(x)])²

sum[x²*f(x)]= 20²*0.05 +25²*0.2 +30²*0.25 +35²*0.15 +40²*0.15 +45²*0.1 +50²*0.1

sum[x²*f(x)]=20+1255+225+183.75+240+202.5+50

sum[x²*f(x)]=1246.25

V(x)=1246.25-(34.25)²

V(x)=73.1875

Standard deviation of x=SD(x)=√V(x)

SD(x)=8.555

3 0
2 years ago
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