The pH of a solution is a measure used to evaluate the acidity of a solution. It is related to the hydronium ion concentration in the solution. It is expressed as pH = -log [H+]. Also, it is related to pOH by the equation 14 = pH + pOH. It is stated that the substance given in the problem is a strong base which means that it completely dissociates into ions. It dissociates as follows:
Ba(OH)2 = Ba^2+ + 2OH-
To determine the pH of the solution, we need to determine the OH- concentration. Then, find pOH. We do as follows:
[OH-] = 0.0064 mol Ba(OH)2 / L ( 2 mol OH- / 1 mol Ba(OH)2 ) = 0.0128 mol OH- / L
pOH = -log (0.0128) = 1.8928
pH = 14 - 1.8928 = 12.1072
You would have to go to sephora and check it out
Answer:
(2R,3S)-2-ethoxy-3-methylpentane
and
(2S,3S)-2-ethoxy-3-methylpentane
Explanation:
For this case, we will have as nucleophile. Also, this compound is also in excess. So, we will have as solvent a protic solvent. Therefore the Sn1 reaction would be favored.
The first step would be the carbocation formation followed by the attack of the nucleophile. In this case both isomers would be produced: R and S (see figure).
Balanced chemical equation:
1 Ca3(PO4)2 + 3 SiO2 + 11 C = 2 P + 3 CaSiO + 11 CO
hope this helps!.
This theory was first proposed by Nicklaus Copernicus. Copernicus was a polish astronomer. He first published the heliocentric system in hes book: De revelation erbium comestible, "In revelations of the heavenly bodies," which appeared in 1543. HOPE IT HELP:)