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STatiana [176]
3 years ago
6

considering what you now know about boyle’s law, make a prediction based on the following situation. what would happen to the pr

essure of a gas inside a sealed bottle, of the bottle was squeezed tightly, reducing the volume of the gas by half ? Explain your thoughts.
Chemistry
1 answer:
Tju [1.3M]3 years ago
5 0

Answer:

The pressure would increase because the volume of space the gas takes up decreases once the bottle is squeezed. There is less room for the gas particles to move around meaning more collisions between the particles occur.

Explanation:

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Answer:

The new pressure will be 0.225 kPa.

Explanation:

Applying combined gas law:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

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P_1\text{ and }V_1 are initial pressure and volume at initial temperature T_1.

P_2\text{ and }V_2 are final pressure and volume at initial temperature T_2.

We are given:

P_1=0.29 kPa\\V_1=V\\P_2=?\\V_2=V+50\% of V=1.5 V

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Putting values in above equation, we get:

\frac{0.29 kPa\times V}{248.15 K}=\frac{P_2\times 1.5V}{289.15 K}

P_1=0.225 kPa

Hence, the new pressure will be 0.225  kPa.

4 0
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