A I know it a i just can tell and do the math in my head.
Answer:
Shop A & $400
Step-by-step explanation:
-4.7 + 27.5 + 122.3 = $145.1 (Shop A)
-0. 2 + 14.5 + 130.4 = $144.7 (Shop B)
Difference = 145.1 - 144.7 = $0.4
0.4 × 1000 = $400
<u>Given:</u>
The coin wrapper volume = 27,480 mm³.
The coin diameter = 21.18 mm.
There are 50 such coins.
<u>To find:</u>
The thickness (height) of 1 coin.
<u>Solution:</u>
The 50 coins form a cylinder with a volume of 27,480 mm³.
If the diameter is 21.18 mm, the radius of a coin will be
mm.
The volume of a cylinder 
The volume of all 50 coins is given as 27,480 mm³. We need to determine the height of a single coin.



mm.
So the thickness of 1 coin is 1.5599 mm.
Answer:
Step-by-step explanation:
16 is especially important, so start with it.
F = 5/9 * C + 32 Subtract 32 from both sides.
F - 32 = 5/9 C + 32 - 32 Combine
F - 32 = 5/9 C Multiply both sides by 9/5
9/5(F - 32) = 9/5 * 5/9 C Combine
9/5(F - 32) = C
Fifteen
V = pi * r^2 * h / 3 Multiply both sides by 3
3V = 3*pi * r^2 * h/ 3 Combine
3V = pi * r^2 * h Divide by pi
3V/(pi ) = r^2 * h Divide by r^2
3V / (pi * r^2) = r^2 * h / r^2 Combine
3V / (pi * r^2) = h