[GEOMETRY] Suppose A and B are independent events. what is P(A U B) ?

If side A is twice as long as B and C is 25 using the Pythagorean Theorem,What are the lengths of side A and B? Round to the nea

777dan777 [17]

Answer:

The lengths of side A is 22.4 and B is 11.9.

Step-by-step explanation:

Given:

If side A is twice as long as B and C is 25 using the Pythagorean Theorem.

Now, to find the lengths of side A and B.

Let the side B be $x.$

So, the side A be $2x.$

Side C = 25.

Now, to solve by using Pythagorean Theorem:

A² + B² = C²

$(2x)^2+(x)^2=(25)^2$

$4x^2+x^2=625$

$5x^2=625$

Dividing both sides by 5 we get:

$x^2=125$

Using square root on both sides we get:

$x=11.18.$

B rounding to the nearest tenth = 11.9.

Now, to get A by substituting the value of $x$ :

$2x\\=2\times 11.18\\=22.36.$

A rounding to the nearest tenth = 22.4.

Therefore, the lengths of side A is 22.4 and B is 11.9.

8 0

3 years ago

Which of the following equations have no solutions? Choose all answers that apply:

Marianna [84]

Answer:

All

Step-by-step explanation:

3 0

2 years ago

Mel randomly selects a coin 150 times selecting a dime 30 times, the experimental probability is 1/5 what is the theoretical pro

Stolb23 [73]

Answer:

Step-by-step explanation:

We can calculate probability by looking at the outcomes of an experiment or by reasoning What is the theoretical probability that a fair coin lands on heads? Choose 1 answer: Random numbers for experimental probability. This means that if we roll a die 60 times we can expect each of the six faces to come up.

Hope this helps.

Please give me brainliest if it is correct

6 0

3 years ago

A cone is 10 inches tall and has a radius of 3 inches. What is the cone's volume?

Mandarinka [93]

The Answer is 94.2 cubic inches

7 0

3 years ago

Suppose Upper F Superscript prime Baseline left-parenthesis x right-parenthesis equals 3 x Superscript 2 Baseline plus 7 and Upp

Sedaia [141]

It looks like you're given

F'(x) = 3x² + 7

and

F (0) = 5

and you're asked to find F(b) for the values of b in the list {0, 0.1, 0.2, 0.5, 2.0}.

The first is done for you, F (0) = 5.

For the remaining b, you can solve for F(x) exactly by using the fundamental theorem of calculus:

$F(x)=F(0)+\displaystyle\int_0^x F'(t)\,\mathrm dt$

$F(x)=5+\displaystyle\int_0^x(3t^2+7)\,\mathrm dt$

$F(x)=5+(t^3+7t)\bigg|_0^x$

$F(x)=5+x^3+7x$

Then F (0.1) = 5.701, F (0.2) = 6.408, F (0.5) = 8.625, and F (2.0) = 27.

On the other hand, if you're expected to approximate F at the given b, you can use the linear approximation to F(x) around x = 0, which is

F(x) ≈ L(x) = F (0) + F' (0) (x - 0) = 5 + 7x

Then F (0) = 5, F (0.1) ≈ 5.7, F (0.2) ≈ 6.4, F (0.5) ≈ 8.5, and F (2.0) ≈ 19. Notice how the error gets larger the further away b gets from 0.

A better numerical method would be Euler's method. Given F'(x), we iteratively use the linear approximation at successive points to get closer approximations to the actual values of F(x).

Let y(x) = F(x). Starting with x₀ = 0 and y₀ = F(x₀) = 5, we have

x₁ = x₀ + 0.1 = 0.1

y₁ = y₀ + F'(x₀) (x₁ - x₀) = 5 + 7 (0.1 - 0) → F (0.1) ≈ 5.7

x₂ = x₁ + 0.1 = 0.2

y₂ = y₁ + F'(x₁) (x₂ - x₁) = 5.7 + 7.03 (0.2 - 0.1) → F (0.2) ≈ 6.403

x₃ = x₂ + 0.3 = 0.5

y₃ = y₂ + F'(x₂) (x₃ - x₂) = 6.403 + 7.12 (0.5 - 0.2) → F (0.5) ≈ 8.539

x₄ = x₃ + 1.5 = 2.0

y₄ = y₃ + F'(x₃) (x₄ - x₃) = 8.539 + 7.75 (2.0 - 0.5) → F (2.0) ≈ 20.164

4 0

3 years ago