[GEOMETRY] Suppose A and B are independent events. what is P(A U B) ?

Which is the best estimate for the average rate of change for the quadratic function graph on the interval 0 ≤ x ≤ 4?

tatuchka [14]

Answer:

The best estimate for the average rate of change is $-2$

Step-by-step explanation:

we know that

the average rate of change using the graph is equal to

$\frac{f(b)-f(a)}{b-a}$

In this problem we have

$f(a)=f(0)=0$

$f(b)=f(4)=-8$

$a=0$

$b=4$

Substitute

$\frac{-8-0}{4-0}=-2$

4 0

3 years ago

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The graph of a proportional relationship contains the point (-30, 18)

Elena L [17]

Answer:

$k=-\frac{3}{5}$

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

we have the point (-30,18)

so

x=-30, y=18

Find the value of k

$k=\frac{y}{x}$

substitute

$k=\frac{18}{-30}$

Simplify

Divide by 6 both numerator and denominator

$k=-\frac{3}{5}$

4 0

3 years ago

(-3)-(-19) I got -22 am I right?

N76 [4]

Answer:

16

Step-by-step explanation:

the negative outside the parenthesis removes the negative that is with the 19 and it is going to be 19-3 which equal 16

4 0

3 years ago

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In a recent survey, 60% of the community favored building a health center in their neighborhood. If 14 citizens are chosen, find

andreev551 [17]

Answer:

Probability that exactly 5 of them favor the building of the health center is 0.0408.

Step-by-step explanation:

We are given that in a recent survey, 60% of the community favored building a health center in their neighborhood.

Also, 14 citizens are chosen.

The above situation can be represented through Binomial distribution;

$P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....$

where, n = number of trials (samples) taken = 14 citizens

r = number of success = exactly 5

p = probability of success which in our question is % of the community

favored building a health center in their neighborhood, i.e; 60%

<em>LET X = Number of citizens who favored building of the health center.</em>

So, it means X ~ $Binom(n=14, p=0.60)$

Now, Probability that exactly 5 of them favor the building of the health center is given by = P(X = 5)

P(X = 5) = $\binom{14}{5} \times 0.60^{5} \times (1-0.60)^{14-5}$

= $2002 \times 0.60^{5} \times 0.40^{9}$

= 0.0408

Therefore, Probability that exactly 5 of them favor the building of the health center is 0.0408.

4 0

3 years ago

Do bonds reduce the overall risk of an investment portfolio? Let x be a random variable representing annual percent return for t

rjkz [21]

Answer:

COV (all stocks) = 0.55

COV (stocks and bonds) = 0.82

Step-by-step explanation:

Coefficient of Variation is used to measure variability.

It is defined as the ration of standard deviation and the mean.

It can be used to compare variability of two population or two samples.

Formula:

$\text{Coefficient of Variation} = \displaystyle\frac{\text{Standard Deviation}}{\text{Mean}}$

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

x: 14, 0, 39, 25, 32, 27, 28, 14, 14, 15

$Mean = \frac{208}{10} = 20.8$

$Standard~Deviation = \sqrt{\frac{1169.6}{9} } = 11.39$

$Coefficient~of~Variation = \frac{11.39}{20.8} = 0.55$

y = 6, 2, 29, 17, 26, 17, 17, 2, 3, 5

$Mean = \frac{124}{10} = 12.4$

$Standard~Deviation = \sqrt{\frac{924.4}{9} } = 10.13$

$Coefficient~of~Variation = \frac{10.13}{12.4} = 0.82%$

Since coefficient of variation of x is less compared to y, thus it could be said bonds does not reduce overall risk of an investment portfolio.

6 0

3 years ago