Answer:
The tarp needed to complete your tent = 93.67 ft².
Step-by-step explanation:
See the attached figure.
The tent has a shape of a triangular prism.
The size of tarp needed to complete your tent = total surface area of the triangular prism
The length will be 6ft, the width 4 ft and the height 4ft.
Total surface area of the triangular prism = area of the floor(6 ft by 4 ft) + area of 2 triangles( 4 ft and the height 4ft. ) + area of 2 rectangles (edge by 6 ft)
The edge (the hypotenuse) = ![\sqrt{4^2+2^2} =\sqrt{16+4}= \sqrt{20} =\sqrt{4*5} =2\sqrt{5}](https://tex.z-dn.net/?f=%5Csqrt%7B4%5E2%2B2%5E2%7D%20%3D%5Csqrt%7B16%2B4%7D%3D%20%5Csqrt%7B20%7D%20%3D%5Csqrt%7B4%2A5%7D%20%3D2%5Csqrt%7B5%7D)
Area of the floor = 4 * 6 = 24 ft²
Area of 2 triangles = 2 * (0.5 * width* height) = 2 * 0.5 * 4 * 4 = 16 ft²
Area of 2 sides = 2 * edge * length = 2 * 2√5 * 6 = 24√5 ft²
Total surface area = 24 + 16 + 24√5 = (40 + 24√5) ft²
Expressing as decimal number 40 + 24√5 = 93.67 ft².
so, the tarp needed to complete your tent = 93.67 ft².
Answer: I think B and A
Step-by-step explanation:
Answer:
78.8
Step-by-step explanation:
85+90+65+75+79
=78.8
With DC = AB, you have a pair of sides.
Then with the parallel lines, you get angles 2 and 3 are congruent because they are alternate interior angles.
Finally, side AC is congruent to side AC. That gives you another pair of congruent sides.
You can use SAS.