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anyanavicka [17]

3 years ago

9

What does Ctrl+O beside the open option on the file menu represent? A. full name of the option B. keystroke alternative to open

a file C. shortcut to display a submenu

2 answers:

Keith_Richards [23]3 years ago

8 0

I would say the answer is B

SpyIntel [72]3 years ago

4 0

B)
it also go to download in the file

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Which equation is a related equation

ki77a [65]

D , because 28-9=21 and 21=x

4 0

3 years ago

If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the

Brrunno [24]

Answer:

$\left(100\pi - 150\sqrt{3}\right)$ square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be $10$ inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment $\sf CH$ be a height on side $\sf AB$ . Since this triangle is equilateral, the size of each internal angle will be $\sf 60^\circ$ . The length of segment

$\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}$ .

The area (in square inches) of this equilateral triangle will be:

$\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}$ .

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

$\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}$ .

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is $10$ inches, the radius of this circle will also be $10$ inches.

The area (in square inches) of a circle of radius $10$ inches is:

$\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi$ .

The area (in square inches) of the circle that the hexagon did not cover would be:

$\begin{aligned}&\text{Area of circle} - \text{Area of hexagon} \\ &= 100\pi - 150\sqrt{3}\end{aligned}$ .

3 0

3 years ago

List four ratios that are equivalent to 10:4

NNADVOKAT [17]

5:2 20:8 30:12 60:16

3 0

3 years ago

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Joaquin has a grade of 81 and 70 on her first two algebra test if she wants an average of 73 what possible score can she get on

Anvisha [2.4K]

81 + 70 + x = 3(73)
first multiply 3(73)

81 + 70 + x = 219
combine like terms

151 + x = 219
subtract 151 from both sides

x = 68

Joaquin needs to score a 68 on her next test to maintain an average of 73.

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3 years ago

What is the root of 20

belka [17]

1000000000000000000000000000

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3 years ago

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