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3 years ago

Using the quadratic formula -3x^2+36x=0 to solve, what are the values for a, b and c

Mathematics

1 answer:

Arte-miy333 [17]3 years ago

3 0

Answer:

$a=-3\\b=36\\c=0$

Step-by-step explanation:

The values of a, b, c, are:

a is whatever is in front of $x^2$ term (including sign)
b is whatever is in front of $x$ term (including sign)
c is the constant term (including the sign)

So for $-3x^2+36x=0$ , we clearly see that a is -3, b is 36, and since there is no constant term, c is 0

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Step-by-step explanation:

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Read 2 more answers

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Thepotemich [5.8K]

Answer:

(-3/8)/(-2 3/4) = 3/22

Step-by-step explanation:

Solve the following;

$\frac{\left(-\frac{3}{8}\right)}{\left(-2\frac{3}{4}\right)}$

$=\frac{\left(-\frac{3}{8}\right)}{\left(-\frac{11}{4}\right)}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{-b}=\frac{a}{b}$

$=\frac{\frac{3}{8}}{\frac{11}{4}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a\cdot \:d}{b\cdot \:c}$

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