Using the quadratic formula -3x^2+36x=0 to solve, what are the values for a, b and c

Mathematics

1 answer:

Arte-miy333 [17]4 years ago

3 0

Answer:

$a=-3\\b=36\\c=0$

Step-by-step explanation:

The values of a, b, c, are:

a is whatever is in front of $x^2$ term (including sign)
b is whatever is in front of $x$ term (including sign)
c is the constant term (including the sign)

So for $-3x^2+36x=0$ , we clearly see that a is -3, b is 36, and since there is no constant term, c is 0

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