Question

Using the quadratic formula -3x^2+36x=0 to solve, what are the values for a, b and c

Answer 1

Answer:

$a=-3\\b=36\\c=0$

Step-by-step explanation:

The values of a, b, c, are:

• a is whatever is in front of $x^2$ term (including sign)
• b is whatever is in front of $x$ term (including sign)
• c is the constant term (including the sign)

So for $-3x^2+36x=0$, we clearly see that a is -3, b is 36, and since there is no constant term, c is 0