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Leokris [45]
2 years ago
13

Complete the inequality. (-9/8)/(-2 3/4) ? 3/22 > < =

Mathematics
1 answer:
Thepotemich [5.8K]2 years ago
6 0

Answer:

(-3/8)/(-2 3/4) = 3/22  

Step-by-step explanation:

Solve the following;

\frac{\left(-\frac{3}{8}\right)}{\left(-2\frac{3}{4}\right)}

=\frac{\left(-\frac{3}{8}\right)}{\left(-\frac{11}{4}\right)}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{-b}=\frac{a}{b}

=\frac{\frac{3}{8}}{\frac{11}{4}}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a\cdot \:d}{b\cdot \:c}

=\frac{3\cdot \:4}{8\cdot \:11}

\frac{3}{22}

Thus, \frac{\left(-\frac{3}{8}\right)}{\left(-2\frac{3}{4}\right)} = \frac{3}{22}

<em>~Learn with lenvy~</em>

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Suppose box A contains 4 red and 5 blue poker chips and box B contains 6 red and 3 blue poker chips. Then a poker chip is chosen
sergejj [24]

Answer:

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Coin chosen from box B is red.

Event B: Blue poker chip transferred.

Probability of choosing a red coin:

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P(A) = \frac{7}{10}*\frac{4}{9} + \frac{6}{10}*\frac{5}{9} = \frac{28 + 30}{90} = 0.6444

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6/10 of 5/9. So

P(A \cap B) = \frac{6}{10}*\frac{5}{9} = \frac{30}{90} = 0.3333

What is the probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3333}{0.6444} = 0.5172

0.5172 = 51.72% probability a blue poker chip was transferred from box A to box B, given that the coin just chosen from box B is red

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Step-by-step explanation:

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Step-by-step explanation:

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