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vekshin1
3 years ago
12

Need help to pass PLEASE HELP

Mathematics
2 answers:
My name is Ann [436]3 years ago
6 0

False

Bec idk why I just asked my brother and he said it was false

Sav [38]3 years ago
4 0

Answer:

False

Step-by-step explanation:

The two is a positive number so it would be going up not down.

*negative number= going down positive number= going up*

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Pleas help me fast!
Lunna [17]

Answer:

35

Step-by-step explanation:

17-7+5^2  Divide 28 by 4

17-7+25  5 to the power 2 is 25

10+25     add 25 and 10 and you get 35.

35

4 0
3 years ago
Read 2 more answers
What is the value of g? 0.8 (2 - g) = 3.2
Alina [70]
0.8 (2-g)=3.2 \\ 2-g=4 \\ 2 = 4 + g \\  \\ \boxed {g = -2}
8 0
3 years ago
A washer and a dryer cost $857 combined. The washer costs $93 less than the dryer. What is the cost of the dryer?
Lelechka [254]

Answer:

Dryer cost $475;  Washer cost $382

Step-by-step explanation:

For this problem, we will simply set up a system of equations to find the value of each the washer (variable x) and the dryer (variable y).

We are given the washer and dryer cost $857 together.

x + y = 857

We are also given that the washer cost $93 less than the dryer.

x = y - 93

So to find the cost of the dryer, we simply need to find the value of y.

x + y = 857

x = y - 93

( y - 93 ) + y = 857

2y - 93 = 857

2y = 950

y = 475

So now we have the value of the dry to be $475.  We can check this by simply plugging in the value and see if it makes sense.

x + y = 857

x + 475 = 857

x = 382

And check this value:

x = y - 93

382 ?= 475 - 93

382 == 382

Therefore, we have found the values of both the washer and the dryer.

Cheers.

6 0
4 years ago
what is the equation a line passes through the points p(2,4) q(-1,3)​ A y=3x+10 B y=x+10 C -x-10 D y=3x-8​
ololo11 [35]

Answer:

D

Step-by-step explanation:

5 0
3 years ago
Two cars leave the same location traveling in opposite directions. One car leaves at 3:00 p.m. traveling at an average rate of 5
sergey [27]
Recall your d = rt,   distance = rate * time

thus \bf \begin{array}{lccclll}
&distance&rate&time(hrs)\\
&-----&-----&-----\\
\textit{first car}&d&55&x\\
\textit{second car}&380-d&75&x+1
\end{array}\\\\
-----------------------------\\\\

\begin{cases}
\boxed{d}=(55)(x)\\\\
380-d=(75)(x+1)\\
----------\\
380-\left( \boxed{(55)(x)} \right)=(75)(x+1)
\end{cases}

notice, the first car leaves at "x" time, the other leaves on hour later, or x + 1

the first car travels some distance "d", whatever that is, thus
the second car, picks up the slack, or the difference, they're 380 miles
apart, thus the difference is 380-d
8 0
3 years ago
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