Question

Can somebody tell me if I did it right I’m not sure how I’m supposed to find the distance?

Answer 1

Answer:

6.4 units

Step-by-step explanation:

Use the distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$d=\sqrt{(8-3)^2+(-3-(-7))^2}$

$d=\sqrt{(5)^2+(4)^2}$

$d=\sqrt{25+16}$

$d=\sqrt{41}$

$d=6.4$

Therefore, the distance between (3,-7) and (8,-3) is 6.4 units

Hopefully, this was helpful!

Answer 2

Answer:

6.4

Step-by-step explanation:

the distance = √[(-3+7)²+(8-3)²]

(leg1=4 , leg2=5)

=√(4²+5²)=√(16+25)=√41 = 6.4