The required maximum value of the function C = x - 2y is 4.
Given that,
The function C = x - 2y is maximized at the vertex point of the feasible region at (8, 2). What is the maximum value is to be determined.
<h3>What is the equation?</h3>
The equation is the relationship between variables and represented as y =ax +m is an example of a polynomial equation.
Here,
Function C = x - 2y
At the vertex point of the feasible region at (8, 2)
C = 8 - 2 *2
C= 4
Thus, the required maximum value of the function C = x - 2y is 4.
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Answer:
See below
Step-by-step explanation:
<u>Parent function:</u>
<u>Transformed function:</u>
- y = 4(3)⁻²ˣ⁺⁸ + 6, (note. I see this as 8, sorry if different but it doesn't make any change to transformation method)
<u>Transformations to be applied:</u>
- f(x) → f(-x) reflection over y-axis
- f(-x) → f(-2x) stretch horizontally by a factor of 2
- f(-2x) → f(-2x + 8) translate 8 units right
- f(-2x + 8) → 4f(-2x + 8) stretch vertically by a factor of 4
- 4f(-2x + 8) → 4f(-2x + 8) + 6 translate 6 units up
1) (f + g)(2) = 7 + 3 = 10 The answer is C
2) (f - g)(4) = 11 - 15 = -4 The answer is A
3) f(1) = 2(1) + 3 = 5 g(1) = 1² - 1 = 0 The answer is D
4) (f xg ) (1) = 7/3 The answer is B
Calculate least common factor of 12, 15 & 18.
It will be 180.
answer is
<span>B. 150 < N < 200</span>
Answer:
Midpoint....; (0,-6)
Step-by-step explanation:
Midpoint of the segment
= [(sum of x-coordinates) ÷ 2] , [(sum of y-coordinates) ÷ 2]
Midpoint = [( 3 + (-3))÷ 2 , (-5 + (-7))÷ 2]
Midpoint = ( 0/2 , -12/2 )
Midpoint = (0,-6)
