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3 years ago

Can somebody tell me if I did it right I’m not sure how I’m supposed to find the distance?

Mathematics

2 answers:

Salsk061 [2.6K]3 years ago

5 0

Answer:

6.4 units

Step-by-step explanation:

Use the distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$d=\sqrt{(8-3)^2+(-3-(-7))^2}$

$d=\sqrt{(5)^2+(4)^2}$

$d=\sqrt{25+16}$

$d=\sqrt{41}$

$d=6.4$

Therefore, the distance between (3,-7) and (8,-3) is 6.4 units

Hopefully, this was helpful!

balandron [24]3 years ago

4 0

Answer:

6.4

Step-by-step explanation:

the distance = √[(-3+7)²+(8-3)²]

(leg1=4 , leg2=5)

=√(4²+5²)=√(16+25)=√41 = 6.4

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Step-by-step explanation:

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$m = \frac{3 - 7}{3 -(-3)} \\ m = \frac{3 - 7}{3 +3} \\ m = \frac{-4}{6} \\ m = -\frac{2}{3}$

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Now we have the equation but out of all the choices it seemed that all of them are in slope-intercept form all you have to do now is make our equation rewrite it in slope-intercept form.

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<h3>Answer:</h3>

$y = -\frac{2}{3}x +5\\$ is your equation.

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