Answer:
h = √91 cm
Step-by-step explanation:
Apply pythagorean theorem, a² + b² ° c².
Where,
a = ½(6) = 3 cm
b = h
c = 10 cm
Plug in the values
3² + h² = 10²
9 + h² = 100
9 + h² - 9 = 100 - 9
h² = 91
h = √91 cm
The first two numbers between 100 and 150 that have a HCF of 22 are 110 and 132
<h3>Highest common factors</h3>
The greatest common divisor of two or more integers, which are not all zero, is the largest positive integer that divides each of the integers.
According to the question, we are to find two numbers between 100 and
150 that have a HCF of 22.
In order to do that we will<u> multiply 22 by the values 5 and 6</u>
First number = 22 * 5 = 10
Second number = 22 * 6 = 132
Hence the first two numbers between 100 and 150 that have a HCF of 22 are 110 and 132
Learn more on HCF here; brainly.com/question/21504246
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Answer:
This is the answer
Step-by-step explanation:
T2 = t1 - 4 = 9 - 4 = 5
t3 = 5 - 4 = 1
The common difference = -4 so:-
The sequence is 9, 5, 1, -3, -7 ....
