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a_sh-v [17]
3 years ago
15

Can somebody tell me if I did it right I’m not sure how I’m supposed to find the distance?

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
5 0

Answer:

6.4 units

Step-by-step explanation:

Use the distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

d=\sqrt{(8-3)^2+(-3-(-7))^2}

d=\sqrt{(5)^2+(4)^2}

d=\sqrt{25+16}

d=\sqrt{41}

d=6.4

Therefore, the distance between (3,-7) and (8,-3) is 6.4 units

Hopefully, this was helpful!

balandron [24]3 years ago
4 0

Answer:

6.4

Step-by-step explanation:

the distance = √[(-3+7)²+(8-3)²]

(leg1=4 , leg2=5)

=√(4²+5²)=√(16+25)=√41 = 6.4

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Complete the table of inputs and outputs for the given function. F(x)= -5(x+7)
levacccp [35]

The table of inputs that satisfy the given function is (<em>-2, 25), (-1, -30), (0, 35), (1, -40) and (2, -45).</em>

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given the function f(x) = -5(x + 7)

When x = -2; f(-2) = -5(-2 + 7) = -25

When x = -1; f(-1) = -5(-1 + 7) = -30

When x = 0; f(0) = -5(0 + 7) = -35

When x = 1; f(1) = -5(1 + 7) = -40

When x = 2; f(2) = -5(2 + 7) = -45

The table of inputs that satisfy the given function is (<em>-2, 25), (-1, -30), (0, 35), (1, -40) and (2, -45).</em>

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Find out more on equation at: brainly.com/question/13763238

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