<u>Given</u>:
The length of DE is 8 cm and the measure of ∠ADE is 60°.
We need to determine the surface area of the pyramid.
<u>Length of AD:</u>
The length of AD is given by
Length of AD = 8 cm
<u>Slant height:</u>
The slant height EF can be determined using the trigonometric ratio.
Thus, we have;
Thus, the slant height EF is 4√3
<u>Surface area of the square pyramid:</u>
The surface area of the square pyramid can be determined using the formula,
Substituting the values, we have;
The exact form of the area of the square pyramid is 
Substituting √3 = 1.732 in the above expression, we have;
Rounding off to one decimal place, we get;
Thus, the area of the square pyramid is 174.8 cm²
Answer:
B
Step-by-step explanation:
Answer:u=19/7 or 2.714286 or 2 5/7
Step-by-step explanation:
−14u+32=−6
Step 1: Subtract 32 from both sides.
-14u+32-32=-6-32
-14u=-38
Step 2: Divide both sides by -14.
-14u/-14=-38/-14
U=19/7
Answer:
A
Step-by-step explanation:
add
Answer: The velocity of the ball is 108.8 ft/s downwards.
Step-by-step explanation:
When the ball is dropped, the only force acting on the ball will be the gravitational force. Then the acceleration of the ball will be the gravitational acceleration, that is something like:
g = 32 ft/s^2
To get the velocity equation we need to integrate over time, to get:
v(t) = (32ft/s^2)*t + v0
where v0 is the initial velocity of the ball. (t = 0s is when the ball is dropped)
Because it is dropped, the initial velocity is equal to zero, then we get:
v(t) = (32ft/s^2)*t
Which is the same equation that we can see in the hint.
Now we want to find the velocity 3.4 seconds after the ball is dropped, then we just replace t by 3.4s, then we get:
v(3.4s) = (32ft/s^2)*3.4s = 108.8 ft/s
The velocity of the ball is 108.8 ft/s downwards.
