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2 years ago

How to solve the 4a.plz

Mathematics

1 answer:

vladimir1956 [14]2 years ago

3 0

(4xy-2y^2)+2y
4-2=2....x will remain y^1-y^2=y^-1
2xy^-1+2y
answer=2x+2y

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How can u show that two objects are proportional using a graph

Grace [21]

The graph has to be a straight line that pass through the origin (0,0)

3 0

3 years ago

5×=15+10y,3×+7y=31 it's for tomorrow pls

Katarina [22]

Answer:

x = 6.39, y = 1.69 is the solution of the given equation system.

Step-by-step explanation:

Here, the given set of equation is:

5 x = 15 + 10 y ⇒ 5 x - 10 y = 15 ...... (1)

3 x +7 y = 31 ............. (2)

Now, the coefficient of x in first equation id 5 and in second is 3.

So, MULTIPLY (1) with 3 and (2) with -5 , we get:

15 x - 30 y = 45

-15 x- 35 y = -155

<u>ADD BOTH EQUATIONS ,</u> we get:

15 x - 30 y -15 x- 35 y = 45 - 155

or, -65 y = -110

or, y = 110/65 = 1.69

Put y = 1.69 in 3 x +7 y = 31 , we get:

3(x) + 7 (1.69) =31

⇒ 3 x = 19.17 or x = 6.39

Hence, x = 6.39, y = 1.69 is the solution of the given equation system

3 0

2 years ago

What is the answer to 3×+9=42

Tomtit [17]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

App 19.study

HACTEHA [7]

Answer:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

Step-by-step explanation:

Given

$n = 125$

See attachment for proper table

Required

Complete the table

Experimental probability is calculated as:

$Pr = \frac{Frequency}{n}$

We use the above formula when the frequency is known.

For result of roll 2, 4 and 6

The frequencies are 13, 29 and 6, respectively

So, we have:

$Pr(2) = \frac{13}{125} = 0.104$

$Pr(4) = \frac{29}{125} = 0.232$

$Pr(6) = \frac{6}{125} = 0.048$

When the frequency is to be calculated, we use:

$Pr = \frac{Frequency}{n}$

$Frequency = n * Pr$

For result of roll 3 and 5

The probabilities are 0.144 and 0.296, respectively

So, we have:

$Frequency(3) = 125 * 0.144 = 18$

$Frequency(5) = 125 * 0.296 = 37$

For roll of 1 where the frequency and the probability are not known, we use:

$Total \ Frequency = 125$

So:

Frequency(1) added to others must equal 125

This gives:

$Frequency(1) + 13 + 18 + 29 + 37 + 6 = 125$

$Frequency(1) + 103 = 125$

Collect like terms

$Frequency(1) =- 103 + 125$

$Frequency(1) =22$

The probability is then calculated as:

$Pr(1) = \frac{22}{125}$

$Pr(1) = 0.176$

So, the complete table is:

$1 \to 22 \to 0.176$

$2 \to 13 \to 0.104$

$3 \to 18 \to 0.144$

$4 \to 29 \to 0.232$

$5 \to 37 \to 0.296$

$6 \to 6 \to 0.048$

3 0

2 years ago

Sunshine High School claims that 72% of its students complete their homework on a daily basis. Ms. Carter surveyed 80 students a

zimovet [89]

Answer:

Option A)

z equals 0.60 minus 0.72 all over the square root of the quantity 0.72 times 0.28 over 80

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 80

p = 72% = 0.72

$\hat{p} = 60\5 = 0.60$

Formula for z-statistic:

$z = \dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

Putting the values, we get,

$z = \displaystyle\frac{0.60-0.72}{\sqrt{\frac{0.72(1-0.72)}{80}}}\\\\z =\displaystyle\frac{0.60-0.72}{\sqrt{\frac{0.72(0.28)}{80}}} = -2.39$

This, the correct answer is

Option A)

z equals 0.60 minus 0.72 all over the square root of the quantity 0.72 times 0.28 over 80

4 0

3 years ago