All categories

3 years ago

PLLLS helpppp mee this is due now T-T

Mathematics

2 answers:

sp2606 [1]3 years ago

8 0

Answer:

= 2 and 5

Step-by-step explanation:

( 4 - 7x ) + ( 2x - 2 ) = 0

4 - 7x = 2x - 2 = 0

-7x -2x - 2 + 4 = 0

-5x - 2 = 0

-5 x = 0 or -2 = 0

x = 5 x = 2

Amanda [17]3 years ago

5 0

Answer:

Step-by-step explanation:

You might be interested in

a water station is located at the midpoint of ab at what marker on the path is the water station located?

Finger [1]

Answer: Halfway between A and B.

3 0

3 years ago

Find the area of the following figure:

stellarik [79]

Answer:

12m

Step-by-step explanation:

You can break this shape down into a square and a trapezoid. Frist you can find the area of the square by multiplying 2 by 5 to get 10. Then you would find the area of a trapezoid by doing Area = 1/2height(base1+base2). We can find the height by subtracting 5 from 9. (We do this because we know the side of the square is 5m) Therefore the height would be 4m. We know the bases are 2 and 4. From there you can plug those numbers in to the formula. Area=1/2 * 4 (2 + 4)

Area= 1/2 * 4 (6)

Area = 2(6)

Area = 12m

4 0

3 years ago

The roots of the function f(x) = x2 – 2x – 3 are shown. what is the missing number? x = –1 and x =

andrey2020 [161]

we have

$f(x)=x^{2}-2x-3$

Find the roots

Equate the function to zero

$x^{2}-2x-3=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2}-2x=3$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$x^{2}-2x+1=3+1$

$x^{2}-2x+1=4$

Rewrite as perfect squares

$(x-1)^{2}=4$

Square root both sides

$(x-1)=(+/-)2$

$x=1(+/-)2$

$x=1+2=3$

$x=1-2=-1$

therefore

the answer is

$x=3$

5 0

3 years ago

Read 2 more answers

two mountain bikers leave from the same parking lot and head in opposite directions on two different trails. the first rider goe

sveta [45]

Applying the required rule or theorem, it can be concluded that the second biker is farther from the parking lot. The distance of the bikers to the parking lot are:

i. First biker = 17.0 km

ii. Second biker = 20.22 km

The path of travel of both bikers would form a triangle. Applying the Pythagoras theorem to the path of the first biker would give his distance from the starting point. While applying the cosine rule to the path of second rider would gives his distance to the starting point.

Thus,

a. To determine the distance of the first biker from the parking lot.

Let the required distance be represented by x. Applying the Pythagoras theorem, we have:

$hyp^{2}$ = $adj 1^{2}$ + $adj 2^{2}$