Question

105x^6y^5+70x^7y^11/35x^7y^4

Answer 1

Answer:

$3\frac{y}{x} + 2y^{7}$

Step-by-step explanation:

We have to simplify the expression as given below:

$\frac{105x^{6}y^{5} + 70x^{7}y^{11}}{35x^{7}y^{4} }$

As we know that $\frac{a + b}{c} = \frac{a}{c} + \frac{b}{c}$

= $\frac{105x^{6}y^{5}}{35x^{7}y^{4}} + \frac{70x^{7}y^{11}}{35x^{7}y^{4}}$

As we know the property of exponent $\frac{x^{a} }{x^{b} } = x^{a - b}$

= $3x^{6 - 7}y^{5 - 4} + 2x^{7 - 7} y^{11 - 4}$

= $3x^{-1}y^{1} + 2x^{0} y^{7}$

As we know the properties of exponents $a^{-b} = \frac{1}{a^{b} }$ and $a^{0} = 1$

= $3\frac{y}{x} + 2y^{7}$ (Answer)