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Studentka2010 [4]

2 years ago

15

Please help asap…………..

2 answers:

r-ruslan [8.4K]2 years ago

6 0

Answer:

$y = - \frac{1}{2} x + 1$

Over [174]2 years ago

4 0

Answer:

y=-1/2x+1

Step-by-step explanation:

The slope of the line can be found using the rise over run. The rise is how far it goes up or down the y axis and the run is how far it goes left or right on the x-axis. Then put the rise over run and you have your slope.The rise is going down 1, so the value for rise is -1. The run is going 2 to the right, to the value for run is 2. Then rise over run, you end up with -1/2. To find the y-intercept, look at how many units the line is up from the x-axis on the y axis. The line is 1 unit above the x-axis on the y axis, so the y-intercept is 1. Puting the equation together, you get y=-1/2x+1.

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Initially a wheel rotating about a fixed axis at a constant angular deceleration of 0.5 rad/s 2 has an angular velocity of 0 rad

Zigmanuir [339]

Answer:

$\theta = 5.83\ rad$

Step-by-step explanation:

given,

angular deceleration, α = -0.5 rad/s²

final angular velocity,ω_f = 0 rad/s

angular position, θ = 6.1 rad

angular position at 3.9 s = ?

now, Calculating the initial angular speed

$\omega_f^2 = \omega_i^2 + 2 \alpha \theta$

$0 = \omega_i^2 - 2\times 0.5\times 6.1$

$\omega_i = \sqrt{6.1}$

$\omega_i = 2.47\ rad/s$

now, angular position calculation at t=3.9 s

$\theta = \omega_i t + \dfrac{1}{2}\alpha t^2$

$\theta =2.47\times 3.9 - \dfrac{1}{2}\times 0.5\times 3.9^2$

$\theta = 5.83\ rad$

Hence, the angular position of the wheel after 3.9 s is equal to 5.83 rad.

7 0

3 years ago

Help please! Will give brainiest if correct!

frosja888 [35]

Slope is 3/4
You are welcome

4 0

2 years ago

Read 2 more answers

15% of $3.50 useing proportion

Otrada [13]

Answer:

0.525

Step-by-step explanation:

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3 years ago

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100 POINTS FOR BRAINLIEST! according to the image, whats the answer? Answer wisely for the full 100

stepan [7]

Answer:

Step-by-step explanation:

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$A=\frac{\pi r^2}{2} \\=\frac{\pi 1^2}{2} \\=6.283m^2$

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$A=a^2=2^2=4m^2\\6.283+4=10.283m^2$

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Rectangle

$A=wl=8*13=104m^2$

$104-15=89m^2$

3.

Semicircle

$A=\frac{\pi r^2}{2} \\=\frac{\pi 3^2}{2} \\\\=14.137m^2$

Square

$A=a^2=6^2=36$

$36-14.137=21.863m^2$

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3 years ago

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Westkost [7]

Answer:

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Step-by-step explanation:

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