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3 years ago

PLEASE HELP ME!!!! THANK YOU SO SO SO MUCH.

Mathematics

2 answers:

ozzi3 years ago

8 0

Answer:

Option D:

The volume of the larger can is $229.12 in ^3$

Step-by-step explanation:

We know that if two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube.

Let:

z-----> the scale factor

x-----> the volume of the larger can

y-----> the volume of the smaller can

$z^3=\frac{x}{y}$

In this problem we have:

$z=2$

$y=28.64 in^3$

Substitute and solve for x.

$2^3=\frac{x}{28.64}$

$x=2^3*28.64=229.12^3$

Therefore, the answer is $229.12 in ^3$ .

Hope this helps! (brainliest?)

polet [3.4K]3 years ago

4 0

It would be A because everything is doubled

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lilavasa [31]

Given:

$$\frac{\left(\frac{(4 r)^{3}}{15 t^{4}}\right)}{\left(\frac{16 r}{(3 t)^{2}}\right)}$

To find:

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Step 3: Using step 1 and step 2

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