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mr Goodwill [35]
3 years ago
9

What is 2×109102929128829911001​

Mathematics
1 answer:
babunello [35]3 years ago
7 0

Answer:

218,205,858,257,659,822,002

Step-by-step explanation:

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I believe it is A because if you use the slope x it matches with the line.

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There were about 1.22 million Hispanic-owned businesses in 2012 and 1.73 million in 2017.
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Answer:

  f(t) = 1.22·(173/122)^(t/5)

Step-by-step explanation:

(a) An exponential growth (or decay) function can be written using the form ...

  f(t) = (initial value)·(ratio in period)^(t/period)

Here, we're given an initial value of 1.22, a growth ratio of 1.73/1.22 in a period of 5 years, so we can write the function as ...

  f(t) = 1.22·(173/122)^(t/5)

__

(b) In 2038-2012 = 26 years, the value of the function is ...

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Write the number in standard form.<br> 2 x 102
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210

Step-by-step explanation:

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3 years ago
Cam is a corrupt politician. Nobody votes for him except those he pays to do so. It costs Cam exactly $100 dollar to buy each vo
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How many votes does he pay for?

7 0
2 years ago
Read 2 more answers
At the center of espionage in Kznatropsk one is thinking of a new method for sending Morse telegrams. Instead of using the tradi
alexgriva [62]

Answer:

It takes less time sending 5 letters the traditional way with a probability of 36.7%.

Step-by-step explanation:

First we must take into account that:

- The traditional method is distributed X ~ Poisson(L = 1)

- The new method is distributed X ~ Poisson(L = 5)

P(X=x)=\frac{L^{x}e^{-L}}{x!}

Where L is the intensity in which the events happen in a time unit and x is the number of events.

To solve the problem we must calculate the probability of events  (to send 5 letters) in a unit of time for both methods, so:

- For the traditional method:

P(X=5)=\frac{1^{5}e^{-1}}{1!}\\\\P(X=5) = 0.367

- For the new method:

P(X=5)=\frac{5^{5}e^{-5}}{5!}\\\\P(X=5) = 0.175

According to this calculations we have a higher probability of sending 5 letters with the traditional method in a unit of time, that is 36.7%. Whereas sending 5 letters with the new method is less probable in a unit of time. In other words, we have more events per unit of time with the traditional method.

7 0
3 years ago
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